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A shaft position encoder has 4 output. The outputs corresponding to each position are given in the table below. It is desired to design a circuit that shaft position between 0 and 210° → the output f=1 at the other position →f=0 The values not determined by the shaft position will be taken as 0. a) Fill the truth table. b) Reduce the output function as sum of minterms using Karnaugh map. c) Realize this function using logic gates. Shaft position 0° -30 30° -60° 60°-90° 90° 120 150 120° 180 - 210 210 - 240° 240 - 270 270-300 - 330⁰ XOOOOOOHHH OOOOHHOH 300 330 - 360 X1 X2 X3 X4 0 0 0 150 - 180° 0 0 0 1 1 1 0 0 1 1 0 1 0 0 1 1 0 0 0 OOOOOO 1 1 1 0 1 0 1 0 10 0 0 1 1 1 0 OOP C 1 1 1 OH 0 1 1 0 1 X1 X₂ X3 X4 f 0 0 0 0 0 0 0 1 0 0 1 0 0 1 0 1 0 0 1 0 0 1 1 0 1 1 1 1 0 1 0 1 1 0 1 1 1 0 1 1 0 1 1 1 1 1 1 ·lolo 0 0 1 0 1 0 1 0 1 0 1 0 1 0 1

A shaft position encoder has 4 output. The outputs corresponding to each position are given in the table below. It is desired to design a circuit that shaft position between 0 and 210° → the output f=1 at the other position →f=0 The values not determined by the shaft position will be taken as 0. a) Fill the truth table. b) Reduce the output function as sum of minterms using Karnaugh map. c) Realize this function using logic gates. Shaft position 0° -30 30° -60° 60°-90° 90° 120 150 120° 180 - 210 210 - 240° 240 - 270 270-300 - 330⁰ XOOOOOOHHH OOOOHHOH 300 330 - 360 X1 X2 X3 X4 0 0 0 150 - 180° 0 0 0 1 1 1 0 0 1 1 0 1 0 0 1 1 0 0 0 OOOOOO 1 1 1 0 1 0 1 0 10 0 0 1 1 1 0 OOP C 1 1 1 OH 0 1 1 0 1 X1 X₂ X3 X4 f 0 0 0 0 0 0 0 1 0 0 1 0 0 1 0 1 0 0 1 0 0 1 1 0 1 1 1 1 0 1 0 1 1 0 1 1 1 0 1 1 0 1 1 1 1 1 1 ·lolo 0 0 1 0 1 0 1 0 1 0 1 0 1 0 1

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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A shaft position encoder has 4 output. The outputs corresponding to each position are given in the
table below. It is desired to design a circuit that
shaft position between and → the output f=1
at the other position → f=0
The values not determined by the shaft position will be taken as 0.
a) Fill the truth table. 
b) Reduce the output function as sum of minterms using Karnaugh map. 
c) Realize this function using logic gates. 

A shaft position encoder has 4 output. The outputs corresponding to each position are given in the table below. It is desired to design a circuit that shaft position between 0 and 210° → the output f=1 at the other position → f-0 The values not determined by the shaft position will be taken as 0. a) Fill the truth table. b) Reduce the output function as sum of minterms using Karnaugh map. c) Realize this function using logic gates. Shaft position 0° -30° 30° -60° 60° - 90° 90° 120° 120 150 150 - 180° 180 - 210 210° - 240° 240 - 270 270-300 - 330° 300 330 - 360 X1X2 X3 X4 0 0 OOHOOOOHHH OOOOHHOH 0 0 1 1 1 0 0 0 1 0 1 1 0 1 0 0 1 0 OOOOOOH 1 1 0 1 0 0 1 0 1 0 1 10 0 0 1 0 1 1 OOP C 0 1 1 OH 0 1 1 0 1 X1 X₂ X3 X4 f 0 0 0 0 0 0 0 1 0 0 1 0 0 0 1 1 0 1 0 0 1 1 0 1 0 0 1 1 1 0 1 0 1 1 0 1 0 1 0 1 1 1 1 0 0 1 1 0 1 1 1 1 0 1 1 1 1 ·lolo 0 0 OO 0 1 1
Transcribed Image Text:A shaft position encoder has 4 output. The outputs corresponding to each position are given in the table below. It is desired to design a circuit that shaft position between 0 and 210° → the output f=1 at the other position → f-0 The values not determined by the shaft position will be taken as 0. a) Fill the truth table. b) Reduce the output function as sum of minterms using Karnaugh map. c) Realize this function using logic gates. Shaft position 0° -30° 30° -60° 60° - 90° 90° 120° 120 150 150 - 180° 180 - 210 210° - 240° 240 - 270 270-300 - 330° 300 330 - 360 X1X2 X3 X4 0 0 OOHOOOOHHH OOOOHHOH 0 0 1 1 1 0 0 0 1 0 1 1 0 1 0 0 1 0 OOOOOOH 1 1 0 1 0 0 1 0 1 0 1 10 0 0 1 0 1 1 OOP C 0 1 1 OH 0 1 1 0 1 X1 X₂ X3 X4 f 0 0 0 0 0 0 0 1 0 0 1 0 0 0 1 1 0 1 0 0 1 1 0 1 0 0 1 1 1 0 1 0 1 1 0 1 0 1 0 1 1 1 1 0 0 1 1 0 1 1 1 1 0 1 1 1 1 ·lolo 0 0 OO 0 1 1
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