(a) Show that the lines 3x − 5y + 27 = 0 and 10x + 6y − 46 = 0 are perpendicular. slope of 3x − 5y + 27 = 0 m1 = slope of 10x + 6y − 46 = 0 m2 = Since m1·m2 = , the two lines are perpendicular. (b) Find their point of intersection. (x, y) =
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In order to understand XZ plane, it's helpful to understand two-dimensional and three-dimensional spaces. To plot a point on a plane, two numbers are needed, and these two numbers in the plane can be represented as an ordered pair (a,b) where a and b are real numbers and a is the horizontal coordinate and b is the vertical coordinate. This type of plane is called two-dimensional and it contains two perpendicular axes, the horizontal axis, and the vertical axis.
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(a) Show that the lines 3x − 5y + 27 = 0 and 10x + 6y − 46 = 0 are perpendicular.
| slope of 3x − 5y + 27 = 0 |
m1 =
|
| slope of 10x + 6y − 46 = 0 |
m2 =
|
(b) Find their point of intersection.
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