(a) Show that the reproduction rate goes to zero when the sugar level is low; that is lim r(C)= 0. C→0 1.35 Since r is continuous at C= 0, lim r(C)= r(| = 0. - 4 + 0.27 x 10 C→0

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 91E
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A population model is used to describe how the rate of reproduction of organisms depends on the amount of nutrients that are available. The model shows how the rate
of division of E. coli cells depends upon the amount of sugar added to their growth flask. If r is the rate of reproduction (number of divisions in one hour) and C is the
amount of glucose sugar added to the growth medium measured in moles, then the following applies.
1.35C
r(C) =
-4
C+0.27 x 10
Transcribed Image Text:A population model is used to describe how the rate of reproduction of organisms depends on the amount of nutrients that are available. The model shows how the rate of division of E. coli cells depends upon the amount of sugar added to their growth flask. If r is the rate of reproduction (number of divisions in one hour) and C is the amount of glucose sugar added to the growth medium measured in moles, then the following applies. 1.35C r(C) = -4 C+0.27 x 10
(a) Show that the reproduction rate goes to zero when the sugar level is low; that is lim r(C) = 0.
C→0
1.35 ()
Since r is continuous at C = 0, lim r(C) =r(|
= 0.
4
+ 0.27 x 10
C-0
Transcribed Image Text:(a) Show that the reproduction rate goes to zero when the sugar level is low; that is lim r(C) = 0. C→0 1.35 () Since r is continuous at C = 0, lim r(C) =r(| = 0. 4 + 0.27 x 10 C-0
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