A simple horizontal curve of radius 350 ft connects two tangents that form an intersection angle of 72°48'36". Compute for the parts of the curve, including the tangent distance, the length of arc, the long chord, the external distance, and the middle ordinate. Additionally, if the station of the Pl is established as 8 +57.69, find the stations of the PC and the PT. Draw a simple curve using the calculated values.

A simple horizontal curve of radius 350 ft connects two tangents that form an intersection angle of 72°48'36". Compute for the parts of the curve, including the tangent distance, the length of arc, the long chord, the external distance, and the middle ordinate. Additionally, if the station of the Pl is established as 8 +57.69, find the stations of the PC and the PT. Draw a simple curve using the calculated values.

Traffic and Highway Engineering

5th Edition

ISBN:9781305156241

Author:Garber, Nicholas J.

Publisher:Garber, Nicholas J.

Chapter15: Geometric Design Of Highway Facilities

Section: Chapter Questions

Problem 16P

See similar textbooks

Similar questions

A simple curve is connected by tangents that make an angle of 64°. A point “e” along the curve is 220 m along the back tangent and 56 m perpendicular (offset) to the said tangent. The beginning of the curve is located at 9+070. a. What is the radius of the curve? b. What is the tangent distance of the curve? c. What is the length of the long chord? d. What is the station of point “e”? Draw and plot the curve. Compute all of the necessary elements of the curve. Include the proper units/dimensions and round-off the answers to 3 decimal places.
Two tangents AB and BC intersect at point B at chainage 150.5 m. Calculate all the necessary data for setting out a circular curve of radius 100 m and deflection angle 30⁰ by the method of offsets from the long chord
Please include figures and solutions An unsymmetrical parabolic curve has a forward tangent of 5% and a backward tangent of -3%. The length of curve on the left side of the curve is 120m while that of the right side is 90m. If the vertex is at station 5+040 is at elevation 101m, determine the elevation of the curve at station 4+980. ANS. 103.31m
The common tangent AB of a compound curve is 82.38 m. The angles the common tangent makes with the tangents through PC and PT of the compound curve are 21°10' and 15°20', respectively. If the degree of the first curve is 3°30', what is the radius of the second curve? (Please provide the diagram)
Given a crest curve with slopes p=+3.0% and q= -2.0%, Station of PI= 4+350 and elevation of PI =190.500m., if L =250m, determine the station and elevation of the PC and PT. Calculate the elevations at every 20m station for the length of the curve and locate the station and elevation of the highest point of the curve. Also plot the profile of the curve.
A circular curve with a radius of 305m is connected by 160m spiral transition curve to tangents with an intersection angle, Ic=20°. Determine the length of throw. If TS is at 1+540, determine the stationing of ST. Determine the spiral angle.
A compound curve connects three tangents having an azimuths of 250°, 270 ° and 290° respectively. The length of the chord is 340m long measured from the P.C to the P.T of the curve and is parallel to the common tangent having an azimuth 270 °. If the stationing of P.T is 6+000 a) Plot the compound curve b) Compute all of the elements of a compound Curve. c) Determine the stationing by the interval of 20 of the curve
Given the compound curve with the vertex V inaccessible, angles A and B are equal to 16°20’ and 13°30’, respectively. Stationing at B is at 1+125. 92m. Degrees of curve are 3°30’ and 4°00’ for the first and second curve, respectively. It is desired to substitute the compound curve with a simple curve that shall be tangent to the two tangents, TA and TB, and as well as the common tangent TAB. -Include illustrations -Determine the radius of the simple curve and the station the New P.C. and the old P.T.
A simple curve has a radius of 220 m and angle of intersection of 128°. The curve is to be shifted by rotating the forward tangent 24° counterclockwise about PT. If the back and forward tangents are originally having an azimuth (from south) of 222° and 348° respectively, determine the following: a. The radius of the new curve. b. The central angle of the new curve. c. The stationing of new PC if the old PC is at 8+726.32 Draw and plot the curve. Compute all of the necessary elements of the curve. Include the proper units/dimensions and round-off the answers to 3 decimal places.
A simple curve has a radius of 220 m and angle of intersection of 128°. The curve is to be shifted by rotating the forward tangent 24° counterclockwise about PT. If the back and forward tangents are originally having an azimuth (from south) of 222° and 348° respectively. Determine: Radius of the new curve Central angle of the new curve Stationing of new PC if the old PC is at 8+726.32 Draw and plot the curve. Compute all of the necessary elements of the curve. Include the proper units/dimensions and round-off the answers to three decimal places.
For a simple circular curve where the back tangent is due east and the azimuth of the forward tangent equal to 315°. If the middle ordinate is 6.8 m, compute the length of the tangent. Group of answer choices 39.04 22.83 37.00 34.77
A simple curve has back and forward tangent bearings of N20°E and N80°E respectively. The radius of the curve is 250 m. a. What is the external distance of the curve? b. What is the middle ordinate of the curve? c. Determine the station of point A on the curve if it makes a deflection angle of 6° and that PI is at station 1+200.5. Draw and plot the curve. Compute all of the necessary elements of the curve. Include the proper units/dimensions and round-off the answers to 3 decimal places.