A simple pin-connected truss is loaded and supported as shown. The truss is constructed from three aluminum members, each having across-sectional area of A = 1480 mm2. Assume a = 1.3 m, b = 6.0 m, and c= 3.6 m. If P = 55 kN and Q = 75 kN, determine the normalstress in each member.P0←L.Answers:OAB = iOBC= iJAC =iaBMPa (C)MPa (T)MPa (T)

Answered: Image /qna-images/answer/be99d1a0-7dc3-4590-8e27-d47783d15617.jpg

A simple pin-connected truss is loaded and supported as shown. The truss is constructed from three aluminum members, each having a cross-sectional area of A = 1480 mm². Assume a = 1.3 m, b = 6.0 m, and c = 3.6 m. If P = 55 kN and Q = 75 kN, determine the normal stress in each member.

A simple pin-connected truss is loaded and supported as shown. The truss is constructed from three aluminum members, each having a cross-sectional area of A = 1480 mm². Assume a = 1.3 m, b = 6.0 m, and c = 3.6 m. If P = 55 kN and Q = 75 kN, determine the normal stress in each member.

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter11: Columns

Section: Chapter Questions

Problem 11.9.30P

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Concept explainers

Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial load acts perpendicular to the geometric cross-section of the component. Based on the direction of the application of the load, an axial load can be tensile or compressive. The analysis of bodies under the action of axial loads is generally studied under the branch of mechanics, known as statics.

Question

A simple pin-connected truss is loaded and supported as shown. The truss is constructed from three aluminum members, each having a
cross-sectional area of A = 1480 mm2. Assume a = 1.3 m, b = 6.0 m, and c= 3.6 m. If P = 55 kN and Q = 75 kN, determine the normal
stress in each member.
P
0←
L.
Answers:
OAB = i
OBC= i
JAC =
i
a
B
MPa (C)
MPa (T)
MPa (T)

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