ipe Network): 0.225 cu.m./s A 0.1125 cu.m./s L0.1125 cu.m./s Pipe Pipe Length (m) Diameter (cm) 30 30 K АВ 1 915 BC 610 AD BE CF 3 460 460 25 4 20 25 460 915 DE 6. 20 EF 7 610 20 DG 305 25 GH 305 25 GH 10 1525 30 *** Correction: Pipe 9 = Pipe FH closeGet live help whenever you need from online tutors!Try bartleby tutor todayarrow_forward Oh no! Our expert couldn't answer your question.Don't worry! We won't leave you hanging. Plus, we're giving you back one question for the inconvenience.Here's what the expert had to say:Hi and thanks for your question! Unfortunately we cannot answer this particular question due to its complexity. We've credited a question back to your account. Apologies for the inconvenience.Ask Your Question Again27 of 30 questions left this cycleRenews on Dec 25, 2021QuestionA simple pipe network is shown in the figure below. Determine the actual discharges in each pipe using the Hardy-Cross method.With the help of a spreadsheet, perform fifteen (15) iterations to compute the discharges on each pipe.Submit a copy of your solutions reflecting the following:Tabulation or computation of the K values.Assumed discharges of each pipe and its direction for the first trial.1st and last iteration tables only with the correctional discharges for each loop.Illustration showing the actual discharges and direction on each pipe.Hazen-Williams FormulaUse C = 125 Data (Pipe Network):0.225 cu.m./sA0.1125 cu.m./sL0.1125 cu.m./sPipePipeLength (m)Diameter (cm)3030KАВ1915BC610ADBECF34604602542025460915DE6.20EF761020DG30525GH30525GH10152530*** Correction: Pipe 9 = Pipe FH

Hardy cross method: Flows in each pipe create the total inflow is equal to the total outflow at…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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ipe Network): 0.225 cu.m./s A 0.1125 cu.m./s L0.1125 cu.m./s Pipe Pipe Length (m) Diameter (cm) 30 30 K АВ 1 915 BC 610 AD BE CF 3 460 460 25 4 20 25 460 915 DE 6. 20 EF 7 610 20 DG 305 25 GH 305 25 GH 10 1525 30 *** Correction: Pipe 9 = Pipe FH

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Renews on Dec 25, 2021

Question

A simple pipe network is shown in the figure below. Determine the actual discharges in each pipe using the Hardy-Cross method.
With the help of a spreadsheet, perform fifteen (15) iterations to compute the discharges on each pipe.
Submit a copy of your solutions reflecting the following:
- Tabulation or computation of the K values.
- Assumed discharges of each pipe and its direction for the first trial.
- 1st and last iteration tables only with the correctional discharges for each loop.
- Illustration showing the actual discharges and direction on each pipe.
- - Hazen-Williams Formula
  Use C = 125

Data (Pipe Network):
0.225 cu.m./s
A
0.1125 cu.m./s
L0.1125 cu.m./s
Pipe
Pipe
Length (m)
Diameter (cm)
30
30
K
АВ
1
915
BC
610
AD
BE
CF
3
460
460
25
4
20
25
460
915
DE
6.
20
EF
7
610
20
DG
305
25
GH
305
25
GH
10
1525
30
*** Correction: Pipe 9 = Pipe FH

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