A single phase, 250 kVA, 10kV/2kV 60 Hz transformer has the following equivalent circuitparameters referred to the high voltage side, assuming the cantilever equivalent circuit,with exciting branch on transformer primary.RC(HV) = 60.2 kNXm(HV) = 18.44 knReq(HV) = 3.112 nXeq(HV) = 6.27a) Determine the no-load current drawn from the sourceb) Determine the no-load core power lossc) Determine the no-load power factord) Determine the full-load copper loss

Given Single phase transformer 250 KVA,10 Kv/2Kv 60 HzRc(HV)=60.2 kΩ Xm(HV)=18.44…

A single phase, 250 kVA, 10kV/2kV 60 Hz transformer has the following equivalent circuit parameters referred to the high voltage side, assuming the cantilever equivalent circuit, with exciting branch on transformer primary. RCHV) = 60.2 kQ Xm(HV) = 18.44 kQ %3D %3D Req(HV) = 3.112 Q Xeq(HV) = 6.27 S a) Determine the no-load current drawn from the source b) Determine the no-load core power loss

A single phase, 250 kVA, 10kV/2kV 60 Hz transformer has the following equivalent circuit parameters referred to the high voltage side, assuming the cantilever equivalent circuit, with exciting branch on transformer primary. RCHV) = 60.2 kQ Xm(HV) = 18.44 kQ %3D %3D Req(HV) = 3.112 Q Xeq(HV) = 6.27 S a) Determine the no-load current drawn from the source b) Determine the no-load core power loss

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter3: Power Transformers

Section: Chapter Questions

Problem 3.13P: A single-phase 50-kVA,2400/240-volt,60-Hz distribution transformer has a 1-ohm equivalent leakage...

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