A slot machine has 3 dials. Each dial has 30 positions, one of which is "jackpot" position. Assuming each play spins the dials and stops each independently and randomly, what are the odds of one play winning the jackpot? 1. 1/3=0.03 or 3% 2. 3/(30+30+30)=3/90=0.33 or 33% 3. 3/(30x30x30)=3/27000=0.0001 or 0.01% 4. 1/(30x30x30)=1/27000= 0.00003 or 0.003%

Question

A slot machine has 3 dials. Each dial has 30 positions, one of which is "jackpot" position. Assuming each play spins the dials and stops each independently and randomly, what are the odds of one play winning the jackpot?

1. 1/3=0.03 or 3%

2. 3/(30+30+30)=3/90=0.33 or 33%

3. 3/(30x30x30)=3/27000=0.0001 or 0.01%

4. 1/(30x30x30)=1/27000=

0.00003 or 0.003%

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