Part AA small block with mass 0.0400 kg is moving in the xy-plane. The net force on the block isdescribed by the potential-energy functionU(x, y) = (5.50 J/m²)æ² – (3.60 J/m³ )y³.What is the magnitude of the acceleration of the block when it is at the point z = 0.22 m, y = 0.62 m?Express your answer with the appropriate units.ValueUnitsa =SubmitRequest AnswerPart BWhat is the direction of the acceleration of the block when it is at the point a = 0.22 m, y = 0.62 m?Express your answer in degrees.Πνα ΑΣφ?° counterclockwise from the +T-axisSubmitRequest Answer

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Description: Part AA small block with mass 0.0400 kg is moving in the xy-plane. The net force on the block isdescribed by the potential-energy functionU(x, y) = (5.50 J/m²)æ² – (3.60 J/m³ )y³.What is the magnitude of the acceleration of the block when it is at t

Given data as per question U = 5.50x2 - 3.60y3 x = 0.22 y = 0.62

Answered: A small block with mass 0.0400 kg is…

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A small block with mass 0.0400 kg is moving in the ry-plane. The net force on the block is described by the potential-energy function U(x, y) = (5.50 J/m²)æ² – (3.60 J/m²)y³.

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter8: Potential Energy And Conservation Of Energy

Section: Chapter Questions

Problem 50P: A particle of mass 0.50 kg moves along the x -axis with a potential energy whose dependence on x is...

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