Question

A soft tennis ball is dropped onto a hard floor from a height of 1.90 m and rebounds to a height of 1.49 m. (Assume that the positive direction is upward.)

(a) Calculate its velocity just before it strikes the floor.

m/s

(b) Calculate its velocity just after it leaves the floor on its way back up.

m/s

(c) Calculate its acceleration during contact with the floor if that contact lasts 3.50 ms.

m/s^{2}

(d) How much did the ball compress during its collision with the floor, assuming the floor is absolutely rigid?

m

Step 1

Since we only answer up to 3 sub-parts, we will answer the first 3. Please resubmit the question and specify the other subparts (up to 3) you would like answered.

Step 2

Given:

Initial height from which the soft tennis ball is dropped is, h = 1.90 m

The height to which the ball rebounces is, h'=1.49 m

Step 3

Part a

We need to calculate the velocity of the ball just before it strikes.

The ball would free fall under gravity.

Using...

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