A solution contains 2.2 x 103 M in Cu2+ and 0.33 M in LICN. If the K¢ for Cu(CN)42 is 1.0 x 1025, how much copper ion remains at equilibrium?

Chemistry
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ISBN:9781133611097
Author:Steven S. Zumdahl
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Chapter16: Solubility And Complex Ion Equilibria
Section: Chapter Questions
Problem 102CP: Calculate the equilibrium concentrations of NH3, Cu2+, Cu(NH3)2+, Cu(NH3)22+, Cu(NH3)32+, and...
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A solution contains 2.2 × 10-3 M in Cu2+ and 0.33 M in LiCN. If the Kf for Cu(CN)42- is 1.0 × 1025, how much copper ion remains at equilibrium?

 

Answer: 1.9*10^-26

 

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A solution contains 2.2 x 103 M in Cu2+ and 0.33 M in LICN. If the K¢ for Cu(CN)42 is 1.0 x 1025, how much copper ion remains at equilibrium?
Transcribed Image Text:A solution contains 2.2 x 103 M in Cu2+ and 0.33 M in LICN. If the K¢ for Cu(CN)42 is 1.0 x 1025, how much copper ion remains at equilibrium?
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