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A solution is prepared by dissolving 32.5 g of glucose (180.156 g/mol) in 593. g of water (18.015 g/mol). Calculate the molality that solution. Group of answer choices a) 0.531 m b) 3.04 x 10E(-4) m c) 3.29 m d) 0.304 m

A solution is prepared by dissolving 32.5 g of glucose (180.156 g/mol) in 593. g of water (18.015 g/mol). Calculate the molality that solution. Group of answer choices a) 0.531 m b) 3.04 x 10E(-4) m c) 3.29 m d) 0.304 m

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter13: The Chemistry Of Solutes And Solutions
Section: Chapter Questions
Problem 110QRT
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A solution is prepared by dissolving 32.5 g of glucose (180.156 g/mol) in 593. g of water (18.015 g/mol). Calculate the molality that solution.
Group of answer choices
a) 0.531 m
b) 3.04 x 10E(-4) m
c) 3.29 m
d) 0.304 m
Expert Solution
Step 1

Given mass of Glucose = 32.5 gram

Molar mass of Glucose = 180.156 g/mol

Moles of Glucose = 32/180.156 = 0.180  moles

 

 

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