A spinning flywheel has rotational inertia I= 401 kg·m2. Its angular velocity decreases from 20.0 rad/s to zero in 300.0 s due to friction. What is the frictional torque acting? If the frictional force acting is opposite in the direction of the flywheel’s rotation, enter a negative value and if the frictional force acting is in the direction of the flywheel’s rotation, enter a positive value. answer in N m
A spinning flywheel has rotational inertia I= 401 kg·m2. Its
answer in N m
The frictional torque acting on the flywheel can be calculated using the equation of rotational motion:
τ = -I * (dω/dt)
where I is the rotational inertia, ω is the angular velocity, and dω/dt is the angular acceleration.
Since the angular velocity decreases from 20.0 rad/s to zero in 300.0 s.
The angular acceleration can be calculated as:
dω/dt
= -ω/t
= -20.0 rad/s / 300.0 s
= -0.067 rad/s^2
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