A spring is such that a 4-b weight stretches it 6 in. An impressed force coSRr is acting on the spring. If the 4-b weight is started from the equilibrium point with an imparted upward velocity of 4 f/sec, determine the position of the weight as a function of time. u(t) = -2)cos8t u(t) = - ÷(t – 2)sin8t u(t) = -2)sin8t ult) = -극t-2)sin8t

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.7: Applications
Problem 18EQ
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A spring is such that a 4-lb weight stretches it 6 in. An impressed force ;
1
coSst is acting on the spring. If the 4-lb weight is started from the equilibrium point with an imparted upward velocity of 4 ft/sec, determine the position of the
weight as a function of time.
u(t) =
곳(t-2)cos8t
u(t) =
(t - 2)sin8t
u(t) =
능t-2)sin8t
u(t) =
-유t-2)sinBt
Transcribed Image Text:A spring is such that a 4-lb weight stretches it 6 in. An impressed force ; 1 coSst is acting on the spring. If the 4-lb weight is started from the equilibrium point with an imparted upward velocity of 4 ft/sec, determine the position of the weight as a function of time. u(t) = 곳(t-2)cos8t u(t) = (t - 2)sin8t u(t) = 능t-2)sin8t u(t) = -유t-2)sinBt
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