A spring with a 5-kg mass and a damping constant 15 can be held stretched 2 meters beyond its natural length by a force of 8 newtons. Suppose the spring is stretched 4 meters beyond its natural length and then released with zero velocity. In the notation of the text, what is the value c² - 4mk? 145 m²kg²/sec² Find the position of the mass, in meters, after t seconds. Your answer should be a function of the variable t of the form c₁eat + c₂eßt where α = (-15+sqrt145)/10 (the larger of the two) B= (-15-sqrt145)/10 (the smaller of the two) C1 = 15(sqrt145)+145 C₂ -143+15(sqrt145)

Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)
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ISBN:9781305084766
Author:Saeed Moaveni
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Chapter15: Computational Engineering Tools Matlab
Section: Chapter Questions
Problem 14P
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Please find the correct answer for c1 and c2. The answer is wrong even if I switch the two.

A spring with a 5-kg mass and a damping constant 15 can be held stretched 2 meters beyond its natural length by a force of 8 newtons. Suppose the spring is
stretched 4 meters beyond its natural length and then released with zero velocity. In the notation of the text, what is the value c² - 4mk? 145
m²kg²/sec² Find the position of the mass, in meters, after t seconds. Your answer should be a function of the variable t of the form c₁eat + c₂eßt where
a = (-15+sqrt145)/10
(the larger of the two)
ß = (-15-sqrt145)/10
(the smaller of the two)
C₁ =15(sqrt145)+145
C₂ = -143+15(sqrt145)
Transcribed Image Text:A spring with a 5-kg mass and a damping constant 15 can be held stretched 2 meters beyond its natural length by a force of 8 newtons. Suppose the spring is stretched 4 meters beyond its natural length and then released with zero velocity. In the notation of the text, what is the value c² - 4mk? 145 m²kg²/sec² Find the position of the mass, in meters, after t seconds. Your answer should be a function of the variable t of the form c₁eat + c₂eßt where a = (-15+sqrt145)/10 (the larger of the two) ß = (-15-sqrt145)/10 (the smaller of the two) C₁ =15(sqrt145)+145 C₂ = -143+15(sqrt145)
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