A sprinter reaches his maximum speed in 2.6 seconds from rest with constant acceleration. He then maintains that speed and finishes the 100 yards in the overall time of 10.02 seconds. Determine his maximum speed Vmax- t = 0 100 yd- t = 2.6 sec The tolerance is ± 1 in the 3rd significant digit. www.vmax 10.5 i ft/sec t = 10.02 sec

A sprinter reaches his maximum speed in 2.6 seconds from rest with constant acceleration. He then maintains that speed and finishes the 100 yards in the overall time of 10.02 seconds. Determine his maximum speed Vmax- t = 0 100 yd- t = 2.6 sec The tolerance is ± 1 in the 3rd significant digit. www.vmax 10.5 i ft/sec t = 10.02 sec

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter3: Motion Along A Straight Line

Section: Chapter Questions

Problem 112CP: In a 100-rn race, the winner is timed at 11.2 s. The second-place finisher’s time Is 11.6 s. How far...

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here is my problem, I need help: One simple model for a person running the 100 mm dash is to assume the sprinter runs with constant acceleration until reaching top speed, then maintains that speed through the finish line. If a sprinter reaches his top speed of 11.1 m/sm/s in 2.64 ss , what will be his total time? Express your answer in seconds.
Note :: SOLUTION AND ANSWER ONLY NO EXPLANATION NEEDED 1. Solve y = 5e3x + sin x (dy/dx) 2. The velocity of a body as a function of time is given as ν (t) = 5e -2t + 4, where t is in seconds, and v is in m/s. Solve the acceleration in m/s2 at t = 0.6
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