A spy in a speed boat is being chased down a river by government officials in a faster craft. Just as the officials' boat pulls up next to the spy's boat, both reach the edge of a 7.3 m waterfall. If the spy's speed is 11 m/s and the officials' speed is 27 m/s, how far apart will the two vessels be when they land below the waterfall?

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter2: Motion In One Dimension
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A spy in a speed boat is being chased down a river by government officials in a faster craft. Just as the officials' boat pulls up next to the spy's boat, both reach the edge of a 7.3 m waterfall. If the spy's speed is 11 m/s and the officials' speed is 27 m/s, how far apart will the two vessels be when they land below the waterfall?

Expert Solution
Step 1

Time taken by both boats to fall through height 7.3 m is same as their initial velocity in vertical direction is zero and acceleration is same

Time taken  =2h/g = 1.21s

Relative velocity of boats = 27-11 = 16 m/s

Therefore distance of separation = 1.21*16 = 19.36 m

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