A square column foundation is to be constructed on a sand deposit (C = 0). The allowable load Q will be inclined at an angle bØ = 20° with the vertical. Knowing that y = 16.5 KN/ m3 and Df = 1 m. The standard Penetration numbers N60 obtained from the field are as follows. Determine value of qu ? Depth (m) N60 1.5 3 3.0 4.5 6.0 10 7.5 10 -B- 1.25 m-

A square column foundation is to be constructed on a sand deposit (C = 0). The allowable load Q will be inclined at an angle bØ = 20° with the vertical. Knowing that y = 16.5 KN/ m3 and Df = 1 m. The standard Penetration numbers N60 obtained from the field are as follows. Determine value of qu ? Depth (m) N60 1.5 3 3.0 4.5 6.0 10 7.5 10 -B- 1.25 m-

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter16: Shallow Foundations-bearing Capacity

Section: Chapter Questions

Problem 16.5P: A square column foundation has to carry a gross allowable load of 1805 kN (FS = 3). Given: Df = 1.5...

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A 2.0 m wide continuous foundation carries a wall load of 350 kN/m in a clayey soil where = 19.0 kN/m3, c = 5.0 kN/m2, and = 23. The foundation depth is 1.5 m. Determine the factor of safety of this foundation using Eq. (6.28).
A 2.0 m wide strip foundation is placed in sand at 1.0 m depth. The properties of the sand are: γ = 19.5 kN/m3, c′ = 0, and ф′ = 34°. Determine the maximum wall load that the foundation can carry, with a factor of safety of 3.0, using Terzaghi’s original bearing capacity equation with his bearing capacity factors, and Meyerhof’s general bearing capacity equation with shape, depth, and inclination factors from Table 6.3.
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A square column foundation has to carry a gross allowable load of 1805 kN (FS = 3). Given: Df = 1.5 m, = 15.9 kN/m3, =34, and c = 0. Use Terzaghis equation to determine the size of the foundation (B). The applied load on a shallow square foundation makes an angle of 15 with the vertical. Given: B = 1.83 m, Df = 0.91 m, = 18.08 kN/m3, =25, and c = 23.96 kN/m2. Use FS = 4 and determine the gross allowable (vertical component) load. Use Eq. (16.9).
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