for a shallow continuous foundation in a clay, the following data , are given: B = 1.2 m; D; = 1.2 m; b = 0.8 m; H = 6.2 m; ß = 30°; unit weight of , soil = 17.5 kN/m³; ¢ = 0; and c, = 50 kN/m?. Determine the gross allowable bear- ing capacity with a factor of safety FS = 4.

for a shallow continuous foundation in a clay, the following data , are given: B = 1.2 m; D; = 1.2 m; b = 0.8 m; H = 6.2 m; ß = 30°; unit weight of , soil = 17.5 kN/m³; ¢ = 0; and c, = 50 kN/m?. Determine the gross allowable bear- ing capacity with a factor of safety FS = 4.

Principles of Foundation Engineering (MindTap Course List)

8th Edition

ISBN:9781305081550

Author:Braja M. Das

Publisher:Braja M. Das

Chapter5: Ultimate Bearing Capacity Of Shallow Foundations: Special Cases

Section: Chapter Questions

Problem 5.5P

See similar textbooks

Related questions

Q: The centroid of a strip foundation whose width, B, is 5.0 m is located 10 m away from the edge of a…

A: Given: The width of the foundation is 5 m. The vertical cut depth is 4.0 m. The undrained shear…

Q: Question Attached

A: Gross bearing pressure: Gross bearing pressure is a total pressure at the base of the foundation due…

Q: Determine the net ultimate bearing capacity of a mat foundation measuring

A: Given : L = 20m B = 9m Df = 0.5m ϕ = 0 Cu=95 kN/m2

Q: A continuous foundation is shown in Figure 6.24. If the load eccentricity is 0.2 m, determine the…

A: For c'=0 The Meyerhof’s ultimate bearing capacity equation is given by,…

Q: For a flexible foundation with sides 2 m and 3 m and an axial load of 750 kN, determine the elastic…

A: Given- Length of footing L=3 mwidth of footing B=2 mAxial load P=750 kNpoisson's ratio v=0.37E=9.8…

Q: subject : Geotechnical Design Book : PRINCIPLE OF FOUNDATION ENGINEERING

A: We have for elastic settlement the following equation:

Q: It is planned to construct a rectangular foundation with base dimensions of 8 * 14 m (B* L) on the…

Q: For a square foundation, according to the information given and the assumption of vertical load, it…

Q: The concentrically loaded square foundation with dimensions of 2.0mx 2.0m, shown in the given…

A: The flow of fluid includes movement of an unbalanced fluid. As long as unequalled forces are in…

Q: Solve Problem 5.6 using Eq. (5.11).

A: Given- qu=Cu1NcFcsFcd+q

Q: A foundation measuring 1.2 m x 2.4 m in plan is constructed in a saturated clay. Given: depth of…

A: The ultimate uplift capacity of foundations with special reference to transmission tower footings is…

Q: Question attached

A: Solution: Given Data: β=20°FOS=3γ=18 kN/m3c=0B=1.25mD=0.7m Ultimate Bearing capacity…

Q: A continuous foundation is shown in Figure 6.24. If the load eccentricity is 0.2 m, determine the…

A: Solution; Given that; e=0.2 m B=2 m, D.F=1.5 m

Q: For an eccentrically loaded continuous foundation on sand, given B = 1.53 m, Df = 1.59 m, e/B = 0.15…

A: To determine the ultimate load per unit length for the eccentrically loaded continuous foundation.…

Q: The shallow foundation shown in Figure 4.24 measures 1.5 m x 2.25 m and is subjected to a centric…

A: Given:- 1.5m x 2.25 meB=0.12 meL=0.36md=0.8mFOS=4γ=17kN/m3∅=35oc'=0To find:-allowable load the…

Q: 2 ft 24 ft 24 ft 24 ft 2 ft Problem 4 B E F G 3 ft DL=190 kip DL-100 kip DL=180 kip LL = 60 kip LL=…

A: Given data: Size of the mat = 76 ft by 96 ft Column size = 24 in. by 24 in. qall(net)=1.5 kip/ft2…

Q: For an eccentrically loaded continuous foundation on sand, given B = 2.35 m, Df = 1.78 m, e/B = 0.17…

Q: A square column foundation carries a load of 440 kN and has a footing dimension of 1.5 m by 1.5 m.…

A: Given, load =440 KN Footing dimension =1.5m x 1.5m Clay layer settlement

Q: Question attached

A: Given:- D=1mcolumn load =1500kNc'=15kN/m2∅'=24γ=18.5kN/m3To find:-B

Q: The shallow foundation is shown in Figure 4.24 measures 1.5 m X 2.25 m and is subjected to a centric…

A: Given :

Q: n the following example, a rectangular foundation must be designed whose B/L ratio must be equal to…

A: step 1-

Q: Question attached

A: GIVEN DATA:- LENGTH L=1.5M WIDTH B=1M DEPTH D=1M SOIL FRICTION ANGLE=25 COHESION C=50KPA UNIT WEIGHT…

Q: 2. The column load of a square foundation (Figure 1) is given. If the depth of foundation D= 4 ft,…

A: Solution Since you have asked multiple question, we will solve the first question for you. Given…

Q: For the design of an eccentrically loaded shallow foundation, given the following: Soil: y = 19…

Q: A square foundation of 5 m x 5 m is to be founded at a depth of 3 m in a deep layer of sand of unit…

A: (i) For ϕ=25° Refer the table for Terzaghi bearing capacity factors, we get Nc=25.1Nq=12.7Nγ=9.7

Q: 8.4 A rectangular foundation is shown in Figure P8.2, given B = 2 m, L= 4m q = 240 kN/m², H = 6 m,…

A: Part - 1 - Average elastic settlement - Se = qB1 - μ2EIfhere,q = foundation pressure = 240KNm2B =…

Q: A square shallow foundation (B × B) is planned to be constructed on a normality consolidated (NC)…

A: Given data load = 500 KN Foundation is square that means Same dimensions Depth of foundation= 2m…

Q: With respect to Hansen's equations, for a foundation that is 1.5×3.5 in plan, C = 25 kPa and p =…

Q: H.Q 1 Consider a rectangular foundation. Given: B = 1.5 m, L = 2.5 m, Df = 1.2 m, H =0.9 m, o' =…

A: The given data is as follows: Rectangular foundation,B=1.5 mL=2.5 mDf=1.2 mH=0.9 mϕ'=40∘c'=0γ=17…

Q: An eccentrically loaded continuous foundation is shown in Figure P4.11. Determine the ultimate load…

A: Determining the centric ultimate bearing capacity with the help of relation qult…

Q: For an eccentrically loaded continuous foundation on sand, given B = 1.8 m, Df = 0.9 m, e/B = 0.12…

A: The given data is shown below:

Q: " (a) Qu 3 10 B (b) M M → X M₁ Q.₁ (c) M₁ Qu (d) Figure 4.24 Analysis of foundation with two-way…

Q: Refer to Figure 5.2. A square foundation measuring 1.5 m x 1.5 m is supported by a saturated clay…

A: Given DF=1 m Cu=115 kN/m2 width of footing,B=1.5 m γsoil =18.5kN/m3 since the soil is undrained…

Q: subject : Geotechnical Design Book : PRINCIPLE OF FOUNDATION ENGINEERING

A: Given:γ D = 105 lb/ft³, γ B (sat)= 118 lb/ft³B= 5ftD2= 4ftD1=2ftC= 0Ø=35°

Q: A square column foundation has to carry a gross allowable load of 1805 kN ( FS = 3). Given: D f =…

Q: For an eccentrically loaded continuous foundation on sand, given B = 1.9m, Df = 0.81m, e/B = 0.21…

Q: ELABORATE Try solving the following problem: Practice Problem: A rigid foundation is subjected to a…

A: P = 550KN L = 3m B = 2m Df= 1.5m H = 5m Es= 13500knN/m2 μs = 0.5 It has been asked in the question…

Q: Que a) A square foundation is 2.5 m * 2.5 m in plan. The soil supporting the foundation has an…

Q: A strip foundation under the wall of one building, upper axle load =220KN/m, the depth d is 1.2m.…

Q: A column foundation [ 2.0 m x (1.7m] in size is located at a depth of 1.4 m in a strong cohesive…

A: The following figure shows the sketch of the foundation. Given Data: Length of foundation is L=2 m.…

Q: H.Q 2 A square foundation measuring 1.5 m x 1.5 m is supported by a saturated clay layer of limited…

Q: What will be the net allowable bearing capacity of a foundation planned to be 1.83 m 3 1.83 m? Let…

Q: Question 1) For a shallow foundation measuring (1.7 m x 2.2 m) as shown below: , A. Estimate the…

A: Given, qnet = 1.2 MN/m2 B = 1.7 m

Q: subject : Geotechnical Design Book : PRINCIPLE OF FOUNDATION ENGINEERING

A: We have been given the following information:

Q: 2. The column load of a square foundation (Figure 1) is given. If the depth of foundation D= 4 ft,…

A: Given data: DL= 80 kip LL = 60 kip Total load = 1.4(80)+1.7(60) = 214 kip Cohesion of soil, c = 0…

Question

Explain the problem attached

for a shallow continuous foundation in a clay, the following data ,
are given: B = 1.2 m; D; = 1.2 m; b = 0.8 m; H = 6.2 m; ß = 30°; unit weight of ,
soil = 17.5 kN/m³; ¢ = 0; and c, = 50 kN/m?. Determine the gross allowable bear-
ing capacity with a factor of safety FS = 4.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Consider a continuous foundation of width B = 1.4 m on a sand deposit with c = 0, = 38, and = 17.5 kN/m3. The foundation is subjected to an eccentrically inclined load (see Figure 6.33). Given: load eccentricity e = 0.15 m, Df = 1 m, and load inclination = 18. Estimate the failure load Qu(ei) per unit length of the foundation a. for a partially compensated type of loading [Eq. (6.89)] b. for a reinforced type of loading [Eq. (6.90)]
Refer to Figure 5.2. A square foundation measuring 1.5 m x 1.5 m is supported by a saturated clay layer of limited depth underlain by a rock layer. Given that Df = 1 m, H = 0.7 m, cu = 115 kN/m2, and γ = 18.5 kN/m3, estimate the ultimate bearing capacity of the foundation.
The shallow foundation shown in Figure 4.24 measures 1.5 m x 2.25 m and is subjected to a centric load and a moment. If eB = 0.12 m, eL = 0.36 m, and the depth of the foundation is 0.8 m, determine the allowable load the foundation can carry. Use a factor of safety of 4. For the soil, we are told that unit weight γ = 17 kN/m3, friction angle Φ' = 35°, and cohesion c' = 0.
The shallow foundation shown in Figure 6.25 measures 1.5 m × 2.25 m and is subjected to a centric load and a moment. If eB = 0.12 m, eL = 0.36 m, and the depth of the foundation is 0.8 m, determine the allowable load the foundation can carry. Use a factor of safety of 4. For the soil, we are told that unit weight γ = 17 kN/m3, friction angle ф′ = 35°, and cohesion c′ = 0.
Consider a continuous foundation of width B = 1.4 m on a sand deposit with c' = 0, Φ' = 38° and γ = 17.5 kN/m3. The foundation is subjected to an eccentrically inclined load (see Figure 4.31). Given: load eccentricity e = 0.15 m, Df = 1 m, and load inclination β = 18°. Estimate the failure load Qu(ei) per unit length of the foundation a. for a partially compensated type of loading [Eq. (4.85)] b. for a reinforced type of loading [Eq. (4.86)]
A 2.0 m wide continuous foundation carries a wall load of 350 kN/m in a clayey soil where = 19.0 kN/m3, c = 5.0 kN/m2, and = 23. The foundation depth is 1.5 m. Determine the factor of safety of this foundation using Eq. (6.28).
For an eccentrically loaded continuous foundation on sand, given B = 1.8 m, Df = 0.9 m, e/B = 0.12 (one-way eccentricity), γ = 16 kN/m3, and Φ' = 35°. Using the reduction factor method [Eq. (4.60)], estimate the ultimate load per unit length of the foundation.
In the following exercise, the load capacity (Qu) per meter of length must be calculated for a continuous foundation that has an eccentricity e=1.2m in the width direction of the foundation.
A long foundation 0.6 m wide carries a line load of 100 kN/m. Calculate the vertical stress σz, at a point P, the coordinates of which are x = 2.75 m, and z = 1.5 m, where the x-coordinate is normal to the line load from the central line of the footing.
A continuous foundation with a width of 1 m is located on a slope made of clay soil. Refer to Figure 5.19 and let Df = 1 m, H = 4 m, b = 2 m, γ = 16.8 kN/m3, c = cu = 68 kN/m2, Φ= 0, and β = 60°.a. Determine the allowable bearing capacity of the foundation. Let FS = 3.b. Plot a graph of the ultimate bearing capacity qu if b is changed from 0 to 6 m.
Refer to Figure 5.12. For a rectangular foundation on layered sand, given:●● B = 4 ft, L = 6 ft, H = 2 ft, Df = 3 ft●● γ1 = 98 lb/ft3, Φ'1 = 30º, c'1 = 0●● γ2 = 108 lb/ft3, Φ'2 = 38º, c'2 = 0Using a factor of safety of 4, determine the gross allowable load the foundation can carry.
A square column foundation has to carry a gross allowable load of 1805 kN ( FS = 3). Given: D f = 1.5 m, γ = 15.9 kN/m 3 , ϕ ′ = 34 ° , and c ′ = 0. Use Terzaghi's equation to determine the size of the foundation ( B ). The applied load on a shallow square foundation makes an angle of 15° with the vertical.