A square in the coordinate plane is shown below, with its vertices at A(1, 0), B(1, 1), C(0, 1), and D(0, 0). Since the squared distance between points P(x, y) and Q(a, b) is given by the formula PQ² = (x – a)2 + (y – b)2, we see that PA? = (x- 1)2 + (y- 0)2 = x2 – 2x +1+y² is the squared distance between P and vertex A of the square. Complete parts (a) and (b) below. (a) Find PB?, PC², and PD². Type answers in expanded form.

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter1: Equations And Graphs
Section1.1: The Coordinate Plane
Problem 34E: In these exercises we find the area of plane figures. Plot the points P(5,1),Q(0,6) and R(5,1) on a...
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C(0, 1)|
B(1, 1)
P(x. y)
D(0, 0)
A(1,0)
Transcribed Image Text:C(0, 1)| B(1, 1) P(x. y) D(0, 0) A(1,0)
A square in the coordinate plane is shown below, with its vertices at A(1, 0), B(1, 1),
C(0, 1), and D(0, 0). Since the squared distance between points P(x, y) and Q(a, b) is
given by the formula PQ² = (x – a)2 + (y - b)2, we see that
PA? = (x - 1)2 + (y - 0)2 = x2 – 2x +1+y² is the squared distance between P and vertex A
of the square. Complete parts (a) and (b) below.
(a) Find PB?, Pc², and PD2. Type answers in expanded form.
Transcribed Image Text:A square in the coordinate plane is shown below, with its vertices at A(1, 0), B(1, 1), C(0, 1), and D(0, 0). Since the squared distance between points P(x, y) and Q(a, b) is given by the formula PQ² = (x – a)2 + (y - b)2, we see that PA? = (x - 1)2 + (y - 0)2 = x2 – 2x +1+y² is the squared distance between P and vertex A of the square. Complete parts (a) and (b) below. (a) Find PB?, Pc², and PD2. Type answers in expanded form.
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