A standard solution is prepared by completely dissolving 0.4 grams of CaCl2 and 0.2 grams of MgCO3 salts in 1-Liter DI water in a glass bottle closed to the atmosphere. The equilibrium pH of the standard solution is adjusted to 7.3 using acid-base solutions. Assuming the amounts of acid and based used in the initial pH adjustment is negligible, calculate : Temporary and permanent hardness of the solution as mg/L CaCO3. Total alkalinity and acidity as mg/L CaCO3. Useful information for problem :
A standard solution is prepared by completely dissolving 0.4 grams of CaCl2 and 0.2 grams of MgCO3 salts in 1-Liter DI water in a glass bottle closed to the atmosphere. The equilibrium pH of the standard solution is adjusted to 7.3 using acid-base solutions. Assuming the amounts of acid and based used in the initial pH adjustment is negligible, calculate : Temporary and permanent hardness of the solution as mg/L CaCO3. Total alkalinity and acidity as mg/L CaCO3. Useful information for problem :
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter10: Organic Chemistry
Section: Chapter Questions
Problem 10.19P: 10-19 Write Lewis structures for these ions. (a) HCOf(b) CO32- Bicarbonate ionCarbonate ion (c)...
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A standard solution is prepared by completely dissolving 0.4 grams of CaCl2 and 0.2 grams of MgCO3 salts in 1-Liter DI water in a glass bottle closed to the atmosphere. The equilibrium pH of the standard solution is adjusted to 7.3 using acid-base solutions. Assuming the amounts of acid and based used in the initial pH adjustment is negligible, calculate :
- Temporary and permanent hardness of the solution as mg/L CaCO3.
- Total alkalinity and acidity as mg/L CaCO3.
Useful information for problem :
![CT,CO3 = [H₂CO₂] + [HCO3] + [CO²-]
H₂CO3 ↔ HCO3 + H+
= 10-6.3
= 10-10.3
HCO3 ↔ CO²¯ + H+
Και
Kaz](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F393037b2-7449-4bd7-a188-129f813a1361%2Fe4f63f19-8ae4-4e9b-8f49-98faf631a1f3%2F57w0z6e_processed.png&w=3840&q=75)
Transcribed Image Text:CT,CO3 = [H₂CO₂] + [HCO3] + [CO²-]
H₂CO3 ↔ HCO3 + H+
= 10-6.3
= 10-10.3
HCO3 ↔ CO²¯ + H+
Και
Kaz
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