A steel ball is thrown up with a velocity of 90 m/s from the ground. While coming down, it strikes a glass pan, held at half the height through which it has risen and loses 30% of its velocity in breaking the glass. Determine the time taken to reach the maximum height and the velocity with which it will strike the ground and total time taken to reach the ground.

College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter2: Kinematics
Section: Chapter Questions
Problem 54PE: A ball is thrown straight up. It passes a 2.00-m-high window 7.50 m off the ground on its path up...
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A steel ball is thrown up with a velocity of 90 m/s from the ground. While coming down, it strikes a glass pan, held at half the
height through which it has risen and loses 30% of its velocity in breaking the glass. Determine the time taken to reach the
maximum height and the velocity with which it will strike the ground and total time taken to reach the ground.
Solution
The time taken to reach maximum height in seconds is
The maximum height reached in m is
The velocity of the stone when it hits the ground in m/s is
The total time taken by the stone in seconds is
Transcribed Image Text:A steel ball is thrown up with a velocity of 90 m/s from the ground. While coming down, it strikes a glass pan, held at half the height through which it has risen and loses 30% of its velocity in breaking the glass. Determine the time taken to reach the maximum height and the velocity with which it will strike the ground and total time taken to reach the ground. Solution The time taken to reach maximum height in seconds is The maximum height reached in m is The velocity of the stone when it hits the ground in m/s is The total time taken by the stone in seconds is
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