Question

Asked Dec 6, 2019

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A steel rod 1 meter long and having a mass of 2kg is pinned at one of its ends. A force is applied perpendicularly to the rod at a distance of 75 cm from the pinned end. What is the magnitude of the resulting angular acceleration of the rod?

Irod=2kgm2

Step 1

Given values in the question:

Length of the steel rod, *l = *1 m

Mass of the steel rod, *m *= 2 kg

Distance at which force is applied, *r* = 0.75 m

The expression for the moment of inertia *I *of the rod about one of the end is

Step 2

Consider the applied force as *F*.

The expression for the torque is,

Step 3

Angle between *r* and *F* is 90&d...

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