A steel rod is 3.358 cm in diameter at 35.00°C. A brass ring has an interior diameter of 3.350 cm at 35.00°C. At what common temperature will the ring just slide onto the rod? The linear expansion coefficient of steel is 11.00 × 10-6 1/C°. The linear expansion coefficient of brass is 19.00 × 10-6 1/C°.

A steel rod is 3.358 cm in diameter at 35.00°C. A brass ring has an interior diameter of 3.350 cm at 35.00°C. At what common temperature will the ring just slide onto the rod? The linear expansion coefficient of steel is 11.00 × 10-6 1/C°. The linear expansion coefficient of brass is 19.00 × 10-6 1/C°.

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter16: Temperature And The Kinetic Theory Of Gases

Section: Chapter Questions

Problem 8P

See similar textbooks

Similar questions

A hollow aluminum cylinder 20.0 cm deep has an internal capacity of 2.000 L at 20.0C. It is completely filled with turpentine at 20.0C. The turpentine and the aluminum cylinder are then slowly warmed together to 80.0C. (a) How much turpentine overflows? (b) What is the volume of the turpentine remaining in the cylinder at 80.0C? (c) If the combination with this amount of turpentine is then cooled back to 20.0C, how far below the cylinders rim does the turpentines surface recede?
The outer diameter of a glass jar and the inner diameter of its iron lid are both 760 mm at room temperature (20.0 ∘C). a)What will be the size of the mismatch between the lid and the jar if the lid is briefly held under hot water until its temperature rises to 57.5 ∘C, without changing the temperature of the glass? Use the coefficient of linear expansion for iron α=1.2×10−5K−1.
A 1.0-m-long steel beam, initially at a temperature of 250 C, increases in temperature to 1000 C by inserting it into an insulating jacket for several minutes while the inside of the jacket is subsequently flooded with steam. By how much does the length of the steel beam expand? (The thermal coefficient of linear expansion for steel is 12 x 10-6 (C0)-1) a. 0.90 mm b. 1.0 mm c. 0.70 mm d. 0.80 mm e. 0.60 mm
A brass ring of diameter 10.00 cm at 20.00C is heated and slipped over an aluminum rod of diameter 10.01 cm at 20.00C. Assuming the average coefficients of thermal expansion are constant for brass and aluminum, (a) to what temperature must this combination be cooled to separate them? Is this attainable? (b) What if the aluminum rod is 10.02 cm in diameter
A spherical steel ball bearing has a diameter of 2.540 cm at 26.00°C. (Assume the coefficient of linear expansion of the steel is 1.10 10-5(°C-1), and the average volume expansion coefficient is 3.30 10-5(°C-1).) A) What is its diameter when its temperature is raised to 97.0°C? (Give your answer to four significant figures in cm.) B) What temperature change is required to increase its volume by 1.100%?
A spherical steel ball bearing has a diameter of 2.540 cm at 21.00°C. (Assume the coefficient of linear expansion for steel is 11 ✕ 10−6 (°C)−1. ) (a) What is its diameter when its temperature is raised to 98.0°C? (Give your answer to at least four significant figures.)? cm(b) What temperature change is required to increase its volume by 0.900%? ?°C
A brass ring of diameter 10.00 cm at 20.0°C is heated and slipped over an aluminum rod of diameter 10.01 cm at 20.0°C. Assuming the average coefficients of linear expansion are constant, (a) to what temperature must the combination be cooled to separate the two metals? Is that temperature attainable? (b) What if the aluminum rod were 10.02 cm in diameter?
A hollow aluminum cylinder 15.5 cm deep has an internal capacity of 2.000 L at 22.0°C. It is completely filled with turpentine at 22.0°C. The turpentine and the aluminum cylinder are then slowly warmed together to 80.0°C. (The average linear expansion coefficient for aluminum is 24 ✕ 10−6°C−1, and the average volume expansion coefficient for turpentine is 9.0 ✕ 10−4°C−1.) How much turpentine overflows? 2. What is the volume of turpentine remaining in the cylinder at 80.0°C? (Give your answer to at least four significant figures.) 3. If the combination with this amount of turpentine is then cooled back to 22.0°C, how far below the cylinder's rim does the turpentine's surface recede?
A steel rod is 3.00cm3.00cm in diameter at 25.00∘C25.00∘C. A brass ring has an interior diameter of 2.992cm2.992cm at 25.00∘C25.00∘C. At what common temperature will the ring just slide onto the rod? The coefficients of linear thermal expansion of steel and brass are 11.0×10−6K−111.0×10−6K−1 and 19.0×10−6K−119.0×10−6K−1, respectively
A hollow aluminum cylinder 24.5 cm deep has an internal capacity of 2.000 L at 23.0°C. It is completely filled with turpentine at 23.0°C. The turpentine and the aluminum cylinder are then slowly warmed together to 75.0°C. (The average linear expansion coefficient for aluminum is 24 ✕ 10−6°C−1, and the average volume expansion coefficient for turpentine is 9.0 ✕ 10−4°C−1.) (a) How much turpentine overflows? cm3(b) What is the volume of turpentine remaining in the cylinder at 75.0°C? (Give your answer to at least four significant figures.) L(c) If the combination with this amount of turpentine is then cooled back to 23.0°C, how far below the cylinder's rim does the turpentine's surface recede? cm
A steel sphere with radius 1.0010 cm at 38.0°C must slip through a brass ring that has an internal radius of 1.0000 cm at the same temperature. To what temperature must the brass ring be heated so that the sphere, still at 38.0°C, can just slip through? Coefficient of linear expansion α for brass is 19.0 × 10−6 K−1. in C
A brass ring has an inner diameter exactly 4.000 cm and outer diameter exactly 4.050 cm at 20⁰C. It is to be fitted over an Aluminum rod of diameter exactly 4.004 cm. To what temperature must the aluminum rod be cooled down to, so that the ring just fits over it? Thermal expansion coefficients: Aluminum = 24.0 x 10-6 /ºC: Brass = 19.0 x 10-6 /ºC. details explanation, please