A stone is launched straight upward from the ground, reaches a maximum height of 30.0 m, and then falls back down to the ground. What was the stone's launch speed (that is, its initial speed right after launch)? 589 m/s 24.3 m/s 30.0 m/s 3.06 m/s

College Physics
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ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
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A stone is launched straight upward from the ground, reaches a maximum height of 30.0 m, and then falls back down to the ground. What was the
stone's launch speed (that is, its initial speed right after launch)?
589 m/s
24.3 m/s
30.0 m/s
3.06 m/s
QUESTION 6
For the stone in the previous question (launched from the ground, reaching maximum height of 30.0 m), what was the total duration of the stone's
flight (from launch to landing)?
2.47 s
4.95 s
3.06 s
4.00 s
Transcribed Image Text:A stone is launched straight upward from the ground, reaches a maximum height of 30.0 m, and then falls back down to the ground. What was the stone's launch speed (that is, its initial speed right after launch)? 589 m/s 24.3 m/s 30.0 m/s 3.06 m/s QUESTION 6 For the stone in the previous question (launched from the ground, reaching maximum height of 30.0 m), what was the total duration of the stone's flight (from launch to landing)? 2.47 s 4.95 s 3.06 s 4.00 s
Expert Solution
Step 1

The third equation of motion is 

v2 =u2 + 2 a s

where, v is the final velocity, u is the initial velocity, a is the acceleration and s is the distance. 

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