A straight conductor of length / moves with an acceleration a = 0.1 ms2 at the right angle to the magnetic field of uniform strength B =11.9 T.Calculate 7, considering that the e.m.f., e = Blu, between the ends of the conductor increased from 0 to 5 V during the first 20 s after the beginning ofmotion.Answer:m◆

Magnetic field ( B ) = 11.9 T Acceleration ( a ) = 0.1 ms-2 Time ( t ) = 20 s Voltage ( V ) = 5 V

A straight conductor of length / moves with an acceleration a = 0.1 ms2 at the right angle to the magnetic field of uniform strength B =11.9 T. Calculate 1, considering that the e.m.f., e = Blu, between the ends of the conductor increased from 0 to 5 V during the first 20 s after the beginning of motion. Answer: m +

A straight conductor of length / moves with an acceleration a = 0.1 ms2 at the right angle to the magnetic field of uniform strength B =11.9 T. Calculate 1, considering that the e.m.f., e = Blu, between the ends of the conductor increased from 0 to 5 V during the first 20 s after the beginning of motion. Answer: m +

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter22: Magnetic Forces And Magnetic Fields

Section: Chapter Questions

Problem 63P

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