A student obtains the following data in a calorimetry experiment designed to measure the specific heat of aluminum.Initial temperature of water and calorimeter 70.3°CMass of water0.402 kgMass of calorimeter0.04 kgSpecific heat of calorimeter0.60 kJ/kg.°CInitial temperature of aluminumMass of aluminumFinal temperature of mixture(a) Use these data to determine the specific heat of aluminum.J/kg. °C(b) Is your result within 15% of 900 J/kg . °C?YesNoNeed Help?26.8°C0.199 kg66.4°CRead It

It is given that, the mass of the calorimeter is, mc=0.04 kg, the mass of the water is mw=0.402 kg,…

Answered: A student obtains the following data in…

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter21: Heat And The First Law Of Thermodynamics

Section: Chapter Questions

Problem 68PQ

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A student obtains the following data in a calorimetry experiment designed to measure the specific heat of aluminum.
Initial temperature of water and calorimeter 70.3°C
Mass of water
0.402 kg
Mass of calorimeter
0.04 kg
Specific heat of calorimeter
0.60 kJ/kg.°C
Initial temperature of aluminum
Mass of aluminum
Final temperature of mixture
(a) Use these data to determine the specific heat of aluminum.
J/kg. °C
(b) Is your result within 15% of 900 J/kg . °C?
Yes
No
Need Help?
26.8°C
0.199 kg
66.4°C
Read It

Expert Solution

Introduction:

It is given that,

the mass of the calorimeter is, $m_{c} = 0.04 kg$ ,
the mass of the water is $m_{w} = 0.402 kg$ ,
the mass of the aluminum is, $m_{A l} = 0.199 kg$
the specific heat of the calorimeter is $C_{cl} = 0.60 kJ / kg \cdot {}^{\circ}C$
the specific heat of the water is $C_{w} = 4.187 kJ / kg \cdot ° C$
the initial temperature of water and calorimeter is, $T_{1} = 70.4 ° C$
the initial temperature of the aluminum is $T_{A i} = 26.8 ° C$
the final temperature of the mixture is $T = 66.4 ° C$

It is required to find the specific heat of aluminum, let the specific heat be $C_{A l}$ .

The amount of heat (J) absorbed by a substance per unit mass (Kg) as its temperature rises by 1 K is known as its specific heat capacity, or C.
The amount of heat Q needed to increase the temperature of a substance with mass m, and specific heat c from $T_{1}$ to $T_{2}$ is,

$Q = m c (T_{2} - T_{1})$

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