A student ran the following reaction in the laboratory at 530 K: PC13 (9) + Cl2(g) → PCls (g) When she introduced 0.0935 moles of PC13 (g) and 0.110 moles of Cl₂(g) into a 1.00 liter container, she found the equilibrium concentration of PC1, (g) to be 0.0552 M. Calculate the equilibrium constant, Ke, she obtained for this reaction. Kc =
A student ran the following reaction in the laboratory at 530 K: PC13 (9) + Cl2(g) → PCls (g) When she introduced 0.0935 moles of PC13 (g) and 0.110 moles of Cl₂(g) into a 1.00 liter container, she found the equilibrium concentration of PC1, (g) to be 0.0552 M. Calculate the equilibrium constant, Ke, she obtained for this reaction. Kc =
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 51QRT: At room temperature, the equilibrium constant Kc for the reaction
2 NO(g) ⇌ N2(g) + O2(g)
is 1.4 ×...
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![A student ran the following reaction in the laboratory at 530 K:
PC13 (9) + Cl₂ (g) → PCls (g)
When she introduced 0.0935 moles of
PC13 (g) and 0.110 moles of
Cl₂ (9) into a 1.00 liter container, she found the equilibrium concentration of
PC1, (g) to be 0.0552 M.
Calculate the equilibrium constant, Ke, she obtained for this reaction.
Ke =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd308d19b-12d5-4ce5-860b-78d92f812f1e%2F6d7347a7-f2c4-44fe-ad43-312493dcb516%2Fdi0ztr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A student ran the following reaction in the laboratory at 530 K:
PC13 (9) + Cl₂ (g) → PCls (g)
When she introduced 0.0935 moles of
PC13 (g) and 0.110 moles of
Cl₂ (9) into a 1.00 liter container, she found the equilibrium concentration of
PC1, (g) to be 0.0552 M.
Calculate the equilibrium constant, Ke, she obtained for this reaction.
Ke =
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