A study of 420,095 Danish cell phone users found that 0.0321% of them developed cancer of the brain or nervous system. Use the sample data to construct a 90% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system.

Q: In a survey of 2279 ​adults, 729 say they believe in UFOs. Construct a 90% confidence…

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Q: A survey of 540 depressed shoppers found at 32% of them shop on impulse. What is the 99% confidence…

A: Given : Sample Size, n = 540 confidence level,c=0.99 Significance level, α…

Q: In another pre-election poll, a pollster finds that 438 out of 600 people polled favor, Smith.…

A: Given, X = 438 N = 600 The sample proportion is given by:

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A:

Q: A clinical trial tests a method designed to increase the probability of conceiving a girl. In the…

A: Given,   The sample proportion is,

Q: A study of 420,055 cell phone users found that 137 of them developed cancer of the brain or nervous…

A: From the provided information, Sample size (n) = 420055 Out of which 133 developed cancer of the…

Q: In a survey of 3005 adults aged 57 through 85 years, it was found that 81.7% of them used at least…

A: Given :  n = 3005 p̂=0.817

Q: A Pew Research Center report on gamers and gaming estimated that 49% of U.S. adults play video games…

A:

Q: 3. A survey of 2,950 Filipinos showed that 2,655 trust the Supreme Court decisions on legal issues.…

A: Let X be the number of trust the supreme court decision on legal issues  n be the sample size  Given…

Q: A sample of 100 homes in city A and 100 homes in City B was taken to estimate the proportion of the…

A: Given that, A sample of 100 homes in city A and 100 homes in city B were taken to estimate the…

Q: In a recent poll of 1100 randomly selected adult bicyclists, 26% said they regularly ride their…

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Q: A magazine reports survey results of 600 randomly selected adults bystating that: “65% of those…

A: From the given information, Sample size (n) = 600 Probability that favor gun control (p) =0.65…

Q: A university dean is interested in determining the proportion of students who receive some financial…

A: The point estimate=p^=118200=0.59n=sample size= 200z=critical value of 95% confidence…

Q: In a random sample of 500 people eating lunchbat a cafeteria on various fridays, it was found that…

A: Given X=160 n=500 P=X/n

Q: A Gallup poll of 1001 Americans age 18 and over conducted in May of 2013 found that 80% of the…

A: Solution: From the given information, p-hat=80% and the margin of error is 3.2%.

Q: A recent study of 2700 children randomly selected found 21​% of them deficient in vitamin D. ​…

A: Given that, 2700 children randomly selected found 21​% of them deficient in vitamin D. n=2700p^=0.21…

Q: In a random sample, 136 of 400 people given a flu vaccine experienced some discomfort. Construct a…

A: Given information n = 400 People No of people given vaccine x = 136

Q: In a study of 150 randomly selected accidents that required treatment in an emergency room, 36%…

A:

Q: A study of 420,053 cell phone users found that 130 of them developed cancer of the brain or nervous…

A: Here we need find the 90% confidence interval.

Q: A farmer wants to test the effectiveness of a pest control method in allowing strawberry blooms to…

A: Given that, Sample size n=100 Sample proportion of booms that yield marketable strawberries…

Q: in a survey of 2230 adults, 57% thinks that land travel through a tourist bus is much more reliable…

A: Given,sample size(n)=2230sample proportion(p^)=0.57α=1-0.95=0.05α2=0.025Z0.025=1.96       (from…

Q: A sample of 3048 randomly chosen people found that 341 of them were left-handed. Construct a 99%…

A: Sample proportion=p^=xn=3413048Critical value for 99% confidence interval is=z=2.576n=sample…

Q: Of 91 adults selected randomly from one town, 60 have health insurance. Find a 90% confidence…

A: From the provided information, Sample size (n) = 91 Out of which 60 have health insurance. Sample…

Q: A recent study among 150 street hawkers in Cape Town showed that 48 of them are of the opinion that…

A: Givensample size(n)=150x=48p^=xn=48150p^=0.32confidence interval…

Q: In a poll of 2,500 likely voters, 966 say that the Philippines spend too little on education. Find…

A: Ans- Given the level of confidence interval   90 %                                        Then   α =…

Q: It was observed that 30 of the 100 randomly selected students smoked. Find the confidence interval…

A: It is given that, 30 out of 100 randomly selected students smoked i.e. proportion of the student who…

Q: A survey found that 39 of 66 people who don't drink coffee often have trouble sleeping and 44 of 88…

A: Solution: Let X1 be the number of noncoffee drinkers who have trouble sleeping, n1 be the sample…

Q: In a survey of 1008 adults, a polling agency asked, "When you retire, do you think you will have…

A:

Q: A U.S. Travel Data Center survey of 500 adults found that 195 said they would take more vacations…

A: Solution: Let X be the number of adults who said that they will travel more this year and n be…

Q: In a survey of 1007 parents of children ages 8 to 14, 75% say they are willing to get a second job…

A: Given information- A proportion of parents say they are willing to get a second job or part-time…

Q: When 328 college students are randomly selected and surveyed, it is found that 122 own a car. Find…

A: We want to find 95% CI for population proportion (p)

Q: survey of an urban university showed that 750 of 1,100 students sampled attended a home football…

A:

Q: In a random sample of 100 drivers, 80 were using seat belts while driving. Construct a 95%…

A:

Q: ) In a Gallup poll, 1011 adults were asked if they consume alcoholic beverages and 64% of them said…

A: 11. Given information: The sample size is 1011 adults. 64% of them said that they did. That is,…

Q: A survey conducted by the U.S. department of Labor found the 48 out of 500 heads of households were…

A: Given that, n = 500 x = 48 90% confidence interval

Q: Compute a 95% confidence interval for the difference between the proportion of students favoring…

A:

Q: In a sample of 95 recommendations, it is found that 56% of them made money. Determine the upper…

A: Proportion is almost similar to the concept of probability. Proportion is a fraction of population…

Q: In a survey of 2291 ​adults, 708 say they believe in UFOs.   Construct a 90% confidence interval for…

A:

Q: A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages.  Construct a…

A: Confidence Interval: In statistics, we can say a range of values of the specified population…

Q: Based on a sample of 1000 adult Americans, USA Today reported that 840 of them preferred cheese on…

A: Given that on a sample of 1000 adult Americans, USA Today reported that 840 of them preferred…

Q: According to some car loan statistics, 44% of Americans are relying on an auto loan to pay for their…

A: Givenp^=0.44sample size(n)=1500confidence interval = 95%

Q: In a certain state, a survey of 500 workers showed that 38% belonged to a union.  Find the 93%…

A: Computation of critical value: 1-α=0.93α=0.07α2=0.0351-α2=0.965 The critical value of z-distribution…

Q: In a survey of 1020 adults, a polling agency​ asked, "When you​ retire, do you think you will have…

A: The known values are, The sample proportion is, Critical values: By using the standard normal…

Q: consider a random sample of 300 students in a university, 75 of them declared that they like playing…

A: A random sample of 300 students in a university in which 75 of them declared that they like playing…

Q: In a poll of 2,300 likely voters, 966 say that the Philippines spend too little on education. Find…

A: We have given that the sample size n = 2300, favourable cases X =966 and sample proportion p =…

Q: A survey of 800 women shoppers found that 17% of them shop on impulse. what is 98% confidence…

A:

Q: In a study designed to determine whether there was a cluster of brain cancer cases at a Pratt &…

A: The formula for the 95% confidence interval for the proportion is It is given that record from…

Q: According to a report on sleep deprivation by the Centers for Disease Control and Prevention, the…

A: Given that  p^1=7.8%=0.078p^2=8.7%=0.087n1=11937n2=4892p^=n1p^1+n2p^2n1+n2=0.0806 Confidence…