A study of dorm rooms on a large college campus revealed that 42% had refrigerators, 56% had TVs, and 26% had both a TV and a refrigerator. What is the probability that a randomly selected dorm room has a TV, given that it has a refrigerator? O 1.6154 O 2.1538 0.26 0.4643
A study of dorm rooms on a large college campus revealed that 42% had refrigerators, 56% had TVs, and 26% had both a TV and a refrigerator. What is the probability that a randomly selected dorm room has a TV, given that it has a refrigerator? O 1.6154 O 2.1538 0.26 0.4643
Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter2: The Integers
Section2.7: Introduction To Coding Theory (optional)
Problem 7E
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Please see below. I need this asap please and thank you. Need these asap please and thank you.
Expert Solution
Step 1
Given that :
A represents the refrigerator
B represents the T. V.
P(A) = 42% ; p(B) = 56%
P( A& B) = 36 %
By using conditional probability rule..
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