A survey asked 857 people how many times per week they dine out at a restaurant. The results are presented in the following table. Number of Times Frequency 136 1 254 2 233 3 104 4 74 21 28 7 7 Total 857 Consider the 857 people to be a population. Let X be the number of times per week a person dines out for a person sampled at random from this population. Compute the standard deviation. A) 1.9 B) 2.1 C) 1.5 D) 2.3

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A: nA = 4 , nB = 5 , nC = 6 N = nA+ nB +nC 15

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Q: Find the standard deviation, s, of sample data summarized in the frequency distribution table below…

A: Solution: Class(1) Frequency (f)(2) Mid value (x)(3) f⋅x(4)=(2)×(3) f⋅x^2=(f⋅x)×(x)(5)=(4)×(3)…

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Q: Consider the data with analysis shown in the following computer output: Level N Mean StDev A…

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Q: Consider the data with analysis shown in the following computer output: Level N Mean StDev A…

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Q: Consider the data with analysis shown in the following computer output: Level N Mean StDev A 5…

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Q: Consider the data with analysis shown in the following computer output: Level N Mean StDev A 7…

A: nA= 7, nB= 5 , nC = 5, nD = 7 __________________________________ N = 7+5+5+7 = 24

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A: Provided data is:   CNN Fox Local 45 15 72 12 43 37 18 68 56 38…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.