A survey is being planned to determine the mean amount of time corporation executives watch television. A pilot survey indicated that the mean time per week is 20 hours, with a standard deviation of 5.5 hours. It is desired to estimate the mean viewing time within 30 minutes. The 95% level of confidence is to be used. (Use  z Distribution Table.)How many executives should be surveyed? (Round your z-score to 2 decimal places and round up your final answer to the next whole number.)

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Asked Nov 18, 2019
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A survey is being planned to determine the mean amount of time corporation executives watch television. A pilot survey indicated that the mean time per week is 20 hours, with a standard deviation of 5.5 hours. It is desired to estimate the mean viewing time within 30 minutes. The 95% level of confidence is to be used. (Use  z Distribution Table.)

How many executives should be surveyed? (Round your z-score to 2 decimal places and round up your final answer to the next whole number.)

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Expert Answer

Step 1

The sample size formula is given below:

The sample size formula is given below:
(Zoa
Where, is the population standard deviation, E is the margin of emror and Zg is the critical
value at alevel of significance.
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The sample size formula is given below: (Zoa Where, is the population standard deviation, E is the margin of emror and Zg is the critical value at alevel of significance.

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Step 2

It is given that the mean time per week is 20 hours and a standard deviation of 5.5 hours.

That is, u20 and o 5.5
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That is, u20 and o 5.5

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Step 3

It is desired to estimate the mean time within 30 minutes. The significance level is 0.05.

Conve...

E 0.5
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E 0.5

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