A tank contains 100 kg of salt and 2000 L of water. A solution of a concentration 0.025 kg of salt per liter enters a tank at the rate 7 L/min. The solution is mixed and drains from the tank at the same rate. a.) What is the concentration of our solution in the tank initially? concentration 100/2000 b.) Find the amount of salt in the tank after 5 hours. amount = e^(-7*5*60/2000)*2000 (kg/L) (kg) concentration 0.025 c.) Find the concentration of salt in the solution in the tank as time approaches infinity. (kg/L)
A tank contains 100 kg of salt and 2000 L of water. A solution of a concentration 0.025 kg of salt per liter enters a tank at the rate 7 L/min. The solution is mixed and drains from the tank at the same rate. a.) What is the concentration of our solution in the tank initially? concentration 100/2000 b.) Find the amount of salt in the tank after 5 hours. amount = e^(-7*5*60/2000)*2000 (kg/L) (kg) concentration 0.025 c.) Find the concentration of salt in the solution in the tank as time approaches infinity. (kg/L)
Chapter3: Functions
Section3.3: Rates Of Change And Behavior Of Graphs
Problem 45SE: A driver of a car stopped at a gas station to fill up his gas tank. He looked at his watch, and the...
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Transcribed Image Text:A tank contains 100 kg of salt and 2000 L of water. A solution of a concentration 0.025 kg of salt per liter enters a tank
at the rate 7 L/min. The solution is mixed and drains from the tank at the same rate.
a.) What is the concentration of our solution in the tank initially?
concentration = 100/2000
b.) Find the amount of salt in the tank after 5 hours.
amount = e^(-7*5*60/2000)*2000
(kg/L)
(kg)
concentration = 0.025
c.) Find the concentration of salt in the solution in the tank as time approaches infinity.
(kg/L)
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