Question

Asked Mar 16, 2019

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A tank is shaped like an upside-down square pyramid, with a base with sides that are 4 meters in length and a height of 12meters. If water is being pumped into the pyramid at a rate of 2/3 m^{3} /sec, at what rate is the height of the water increasing when the water is 2 meters deep? (The volume of a pyramid with height h and base area B is given by V=1/3 Bh.)

Enter a fraction and do not include units.

Step 1

We have to find rate of change of height of pyramid.

Information is given below:

Step 2

We will use following rules to find derivative.

Rules are given below:

Step 3

Now with the help of above rules we will differentiate volume equation ,it will give realation between dV/dt and dh/...

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