A tank of water has been outdoors in cold weather, and a slab of ice 6.7 cm thick has formed on its surface (see the figure). The air above the ice is at -6.2°C. Calculate the rate of formation of ice (in centimeters per hour) on the ice slab. Take the thermal conductivity of ice to be 0.0040 cal/s-cm-Co, its density to be 0.92 g/cm%, and its latent heat of fusion to be 333 kJ/kg. Assume no energy transfer through the tank walls or bottom. Air Ice Water

A tank of water has been outdoors in cold weather, and a slab of ice 6.7 cm thick has formed on its surface (see the figure). The air above the ice is at -6.2°C. Calculate the rate of formation of ice (in centimeters per hour) on the ice slab. Take the thermal conductivity of ice to be 0.0040 cal/s-cm-Co, its density to be 0.92 g/cm%, and its latent heat of fusion to be 333 kJ/kg. Assume no energy transfer through the tank walls or bottom. Air Ice Water

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter1: Temperature And Heat

Section: Chapter Questions

Problem 100P: One easy way to reduce heating (and cooling) costs is to add extra insulation in the attic of a...

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An astronaut performing an extra-vehicular activity (space walk) shaded from the Sun is wearing a spacesuit that can be approximated as perfectly white ( e=0 ) except for a 5 cm × 8 cm patch in the form of the astronaut's national flag. The patch has emissivity 0.300. The spacesuit under the patch is 0.500 cm thick, with a thermal conductivity k 0.0600 W/m , and its inner surface is at a temperature of 20.0 . What is the temperature of the patch, and what is the rate of heat loss through it? Assume the patch is so thin that its outer surface is at the same temperature as the outer surface of the spacesuit under it. Also assume the temperature of outer space is 0 K. You will get an equation that is very hand to solve in closed form, so can solve it numerically with a graphing calculator, with software, or even by trial and error with a calculator.
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