A test charge of +2μC is placed halfway between a charge of +6μC and another of +4μC separated by distance 2d = 12 cm. +4uC 9₁ = +4µC +2μC The free body diagram of q₂ from Part 1 should look like this: F3-2 d q2 = +2 μC F1-2 +6μC F3-2 > F1-2 X 93 = +6 μC The force on q2 due to q₁ is repulsive and acts to the right. The force on q2 due to q3 is repulsive and acts to the left. because q391. (a) Calculate the force on the test charge by the +6μC charge. Hint: The force in the positive x-direction is positive and the negative x direction is negative. N (b) Calculate the force on the test charge by the +4μC charge. N (c) Calculate the net force on the test charge by both the charges.
A test charge of +2μC is placed halfway between a charge of +6μC and another of +4μC separated by distance 2d = 12 cm. +4uC 9₁ = +4µC +2μC The free body diagram of q₂ from Part 1 should look like this: F3-2 d q2 = +2 μC F1-2 +6μC F3-2 > F1-2 X 93 = +6 μC The force on q2 due to q₁ is repulsive and acts to the right. The force on q2 due to q3 is repulsive and acts to the left. because q391. (a) Calculate the force on the test charge by the +6μC charge. Hint: The force in the positive x-direction is positive and the negative x direction is negative. N (b) Calculate the force on the test charge by the +4μC charge. N (c) Calculate the net force on the test charge by both the charges.
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter19: Electric Forces And Electric Fields
Section: Chapter Questions
Problem 4P
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