(a) The elevator accelerates upward from rest at a rate of 1.7 for 1.6 s. s2 (i) Newton's Second Law in the y-direction can be written as T= 1 EF,=-1 meg+ 1 •m¸a (ii) Calculate the tension in the cable supporting the elevator. T= 19567 XN (iii) How high has the elevator moved during this time? Ay= (iv) Calculate the velocity of the elevator after this time. m v(t=1.6 s) = %3D S

(a) The elevator accelerates upward from rest at a rate of 1.7 for 1.6 s. s2 (i) Newton's Second Law in the y-direction can be written as T= 1 EF,=-1 meg+ 1 •m¸a (ii) Calculate the tension in the cable supporting the elevator. T= 19567 XN (iii) How high has the elevator moved during this time? Ay= (iv) Calculate the velocity of the elevator after this time. m v(t=1.6 s) = %3D S

Name: An elevator shown below filled with passengers has a mass of 1800 kg.
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Description: An elevator shown below filled with passengers has a mass of 1800 kg. The elevator does motions (a) through (c) in succession. (a) The elevator accelerates upward from rest at a rate of 1.7for 1.6 s.s2(i) Newton's Second Law in the y-direction can be

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter4: The Laws Of Motion

Section: Chapter Questions

Problem 68AP: An object of mass m1 hangs from a string that passes over a very light fixed pulley P1 as shown in...

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