A thin insulating rod is bent into a semicircular arc of radius a, anda total electric charge Q is distributed uniformly along the rod. LetV = 0 at infinity. Find an expression for the electric potential atpoint p, the center of curvature of the arc.

A thin insulating rod is bent into a sernicrcular arc of radius a.

A thin insulating rod is bent into a semicircular arc of radiu a total electric charge Q is distributed uniformly along the / = 0 at infinity. Find an expression for the electric pot point p the center of curvature of the grc

A thin insulating rod is bent into a semicircular arc of radiu a total electric charge Q is distributed uniformly along the / = 0 at infinity. Find an expression for the electric pot point p the center of curvature of the grc

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter26: Electric Potential

Section: Chapter Questions

Problem 45PQ: The charge density on a disk of radius R = 12.0 cm is given by = ar, with a = 1.40 C/m3 and r...

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Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

A thin insulating rod is bent into a semicircular arc of radius a, and
a total electric charge Q is distributed uniformly along the rod. Let
V = 0 at infinity. Find an expression for the electric potential at
point p, the center of curvature of the arc.

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