A thin rod of length ""and uniform charge per unit length "L" lies along the x axis asshown . (a) Show that the electric field at P, a distance d from the rod along its perpendicularbisector, has no x component and is given by E =-sin O,. (b) Using your result to part2πε,dsin O, .(a), show that the field of a rod of infinite length is E =-2πε,dRP

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Answered: A thin rod of length "" and uniform…

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter24: Electric Fields

Section: Chapter Questions

Problem 76PQ

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Similar questions

Calculate the electric field due to a uniformly charged rod of length L, aligned with the x-axis with one end at the origin; at a point P on the z-axis.
The field due to two parallel plates, the left with a negative surface charge density of −6.0 C/m2 whilethe sheet on the right has a positive surface charge density of +9.0 C/m2is given below. Suppose the plates were spaced 0.0020 m apart. We found that, using Gauss’s law that, independent of this distance, • In I the net field points to the left and has magnitude |Enet| = 1.69 × 1011 N/C.• In region II, between the plates, the field has magnitude 8.47×1011 N/C and points to the left• In III it points to the right and has magnitude |Enet| = 1.69 × 1011 N/C.
A rod 50 cm long and 1.0 cm in radius carries a 2.0@mC charge distributed uniformly over its length. Find the approximate mag-nitude of the electric field (a) 4.0 mm from the rod surface, not near either end, and (b) 23 m from the rod.
A “semi-infinite” non-conducting rod (that is, infinite in one direction only) has uniform linear chargedensity(lambda). Show that the electric field at point P makes an angle of 45⁰ with the rod and that this result isindependent of the distance R. To do this, separately find the parallel and perpendicular (to the rod) components of the electric fieldat P, and show that these components are equal
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A semicircle ofradius a is in the first and secondquadrants, with the center of curvatureat the origin. Positive charge+Q is distributed uniformly aroundthe left half of the semicircle, andnegative charge -Q is distributeduniformly around the right half ofthe semicircle (Fig. ). Whatare the magnitude and direction of the net electric field at the originproduced by this distribution of charge?
A positive charge q is released from rest at the originof a rectangular coordinate system and moves under theinfluence of the electric field
A positive charge q = 7.81 μC is spread uniformly along a thin nonconducting rod of lengthL = 15.4 cm. What are the (a) magnitude and (b) direction (relative to the positive directionof the x axis) of the electric field produced at point P, at distance R = 6.00 cm from the rod along itsperpendicular bisector?
Compute for the work done, in millijoules, in moving a 8-nC charge radially away from the center from a distance of 7 m to a distance of 11 m against the electric field inside a non-conducting spherical shell of inner radius 3 m, outer radius 17 m, and total charge 8 mC.
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This equation is for the electric field of a uniform ring which is charged and is at point z which is perpendicular to the center of the ring. (it means z=0 is part of the plane in which the ring is in). R=radius of ring, Q= total charge of ring, k= coulomb's constant. If k=1 units, Q=1 units, R=8 units, what is Ering, z when z=6 units?

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