A Three-phase half-controlled thyristor bridge with 400 V, three-phase, 50 Hz supply is feeding a separately-excited d.c. motor. Armature resistance is 0.2 N, armature rated current is 100 A and back emf constant is 0.25 V/rpm. Determine the no-load speed if the no-load armature current is 5 A and firing angle is 45°. Also determine the firing angle to obtain a speed of 1500 rpm at rated current.
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- The excitation circuit of a free-excited DC motor is a single-phase full- wave uncontrolled rectifier and The armature circuit is fed with a single-phase full-wave controlled rectifier. both rectifiers for AC voltage voltage 220 V(rms) ,is 50 Hz. Excitation O resistance of motor Rf = 100, armature force resistance Ra = 2 0 and motor voltage constant Kv = 0.25 V/(A - r/s). The motor is a fixed 10Nm buy under load a) Draw the driver (converter-motor) power circuit. To rotate with 1200 d/d of the motor, b) Calculate the thyristor assembly. c) When the engine is heavily loaded, with a suitable probability value for supply voltage, armature voltage, armature flow wavelengths draw below. d) Calculate the motor power (total input power). (Note: Va = IaRa + ea, Vf = IfRf, ea = Kv Ifw and Te = Kv Ifla)1. Single phase full converter is used to control the speed of separately excited DC motors. AC supply voltage is 208 V. Motor armature and field resistance are 0.5 2 and 345 2 respectively. The field current is also controlled by a full converter and the field current is set as the maximum possible value. Motor voltage constant is 0.7 V/A-rad/sec. If firing angle is 45° and armature current is 55 A, determine the angular speed of the motor. Assume armature and field current are ripple free.The armature circuit of a free excited direct current motor with a nominal voltage of 600 V is fed from an adjusted direct voltage source. The excitation circuit is also powered from a regulated voltage source. It is used in an application that requires motor speed adjustment. The speed of the motor at the nominal armature voltage was measured as 1600 rpm. All losses of the motor and voltage source and the effect of armature reaction are neglected. It is accepted that the engine is not saturated.Answer the questions below.a) Draw the armature and excitation circuit of the motor and write the formulas for the equivalent circuit.b) If the load moment of the motor at the nominal armature voltage is 420 Nm, then calculate the armature current and the input power of the motor.c) If the armature voltage of the motor is kept constant at 600 V and the excitation current is decreased until the speed reaches 4000 rpm, then calculate the shaft moment. Show this working area on the M = f (W) axis.
- Design a DC motor circuit to drive A fan-type load with a torque equation equal to: TL=1.34×10−7ω2TL=1.34×10−7ω2 N.m The fan speed range is from 500 to 1200 rpm. To achieve the required operation, the armature voltage of the motor is adjusted by a single-phase, full-wave, ac/dc converter. The input voltage and frequency to the converter are 480 V (rms) and 50 Hz. choose the motor type, show the motor rating, αα range, Supply voltage, and frequency, and any required other information Modify the design to automatically adjust the voltage drive the load within the specified speed range. show the control variable, controller type, connection, and controller weights.Design a DC motor circuit to drive A fan-type load with a torque equation equal to: TL=1.34×10−7ω2TL=1.34×10−7ω2 N.m The fan speed range is from 500 to 1200 rpm. To achieve the required operation, the armature voltage of the motor is adjusted by a single-phase, full-wave, ac/dc converter. The input voltage and frequency to the converter are 480 V (rms) and 50 Hz. choose the motor type, show the motor rating, αα range, Supply voltage, and frequency, and any required other information Modify the design to automatically adjust the voltage drive the load within the specified speed range. show the control variable, controller type, connection, and controller weights. design the single-phase, full-wave, ac/ dc converter. show design specifications, the reason for DC motor selection. correct manual circuit, and correct automatic closed-loop control circuitA 48kW, 600V, 1500 rpm separately excited dc motor is controlled by single phase semi-controlled converter. The resistance of the armature is 192 and of the field is 1450. The field circuit is controlled by a single phase fully controlled converter and its firing angle is set to 20. The AC supply voltage to the armature and field converters is a single phase 220V, 60 Hz. The voltage constant is 0.946 V/A rad/s. If the armature converter firing angle is 45 and the speed is 1200 rpm; calculate the armature current and the developed torque.
- One the following is not an advantage of BLDC motor over conventional DC motor. O Less maintenance Long life No risk of explosion or possibility of RF radiation O Low costSelf-Lift P/O Luo- Dc-dc Converter i need explain Drive for seperately excited dc motorA single phase Half wave AC voltage controller has a resistive load of 16 ohms with input supply voltage of 240 V, 50 Hz. The delay angle of the thyristors is, a = 21/5. Determine a) The rms output voltage and current. b) Input power factor and Input current. c) Average output voltage and current.
- A DC chopper is used in regenerative breaking mode of a dc series motor. The dc supply is 600 V, the duty cycle is 70%. The average value of armature current is 100 A. It is continous and ripple free. What is the value of power feedback to the supply ?Problem') A single-phase full-wave AC/AC voltage controller has input rms voltage Vs - 220 V,50 Hz, load R 100 2, and the firing angle a= 60° for the thyristors T1 and T2. Determine the output rms voltage VO and current IO, and the DPF.The current drawn by 220 V dc shunt motor of armature resistance 0.5 ohm and back emf 200 V is