A torque of 1.45 N-m is applied to a thin rod, fixed to rotate about a point through its center. If the rod is 2.50 kg in mass and 1.11 m in length, find the resulting angular acceleration (in rad/s2) of the rod. (The moment of inertia for a thin rod rotating about a point through its center is /= ML2/12)

A torque of 1.45 N-m is applied to a thin rod, fixed to rotate about a point through its center. If the rod is 2.50 kg in mass and 1.11 m in length, find the resulting angular acceleration (in rad/s2) of the rod. (The moment of inertia for a thin rod rotating about a point through its center is /= ML2/12)

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter1: Introduction To Statics

Section: Chapter Questions

Problem 1.19P: Plot the earths gravitational acceleration g(m/s2) against the height h (km) above the surface of...

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