A tractor has a first cost of $40,000 and a salvage value of $15,000 in year 10. The MARR is 12% per year. An identical tractor can be rented for $32,000 per year. Annual :operating cost is same for both options. If x is the minimum number of years the tractor must be used in order to justify its purchase, the relation to find x is represented by 15,000x + 12,000(A/F, 12%, 10) = -32,000x - (A/P, 12%, 10)40,000- O 15,000x + 12,000(A/F, 12%, 10) = 32,000x - (A/P, 12%, 10)40,000- O 12,000x + 15,000(A/F, 10%, 12) = 40,000x – (A/P, 10%, 12)32,000- O 12,000x + 15,000(A/F, 10%, 12) = -40,000x – (A/P, 10%, 12)32,000- O 15,000(A/F, 12%, 10) = -32,000x + (A/P, 12%, 10)40,000- O 15,000(A/F, 12%, 10) = 32,000x + (A/P, 12%, 10)40,000- O None of them O

A tractor has a first cost of $40,000 and a salvage value of $15,000 in year 10. The MARR is 12% per year. An identical tractor can be rented for $32,000 per year. Annual :operating cost is same for both options. If x is the minimum number of years the tractor must be used in order to justify its purchase, the relation to find x is represented by 15,000x + 12,000(A/F, 12%, 10) = -32,000x - (A/P, 12%, 10)40,000- O 15,000x + 12,000(A/F, 12%, 10) = 32,000x - (A/P, 12%, 10)40,000- O 12,000x + 15,000(A/F, 10%, 12) = 40,000x – (A/P, 10%, 12)32,000- O 12,000x + 15,000(A/F, 10%, 12) = -40,000x – (A/P, 10%, 12)32,000- O 15,000(A/F, 12%, 10) = -32,000x + (A/P, 12%, 10)40,000- O 15,000(A/F, 12%, 10) = 32,000x + (A/P, 12%, 10)40,000- O None of them O

College Algebra (MindTap Course List)

12th Edition

ISBN:9781305652231

Author:R. David Gustafson, Jeff Hughes

Publisher:R. David Gustafson, Jeff Hughes

Chapter6: Linear Systems

Section6.8: Linear Programming

Problem 5SC: If during the following year it is predicted that each comedy skit will generate 30 thousand and...

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