A train makes a round trip on a straight, level track. The first half of the trip is 300km and is traveled at a speed of 75 km/m. After a 0.50 h layover, the train returns the 300km at the speed of 85 km/h. What is the train’s (a) average speed and (b) average velocity?

Question
Asked Sep 10, 2019
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A train makes a round trip on a straight, level track. The first half of the trip is 300km and is traveled at a speed of 75 km/m. After a 0.50 h layover, the train returns the 300km at the speed of 85 km/h. What is the train’s (a) average speed and (b) average velocity?

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Expert Answer

Step 1

Given:

For first half of the trip

Distance covered by train s1 = 300 km

Speed of the train v1 = 75 km/h (assumed)

Layover time of the train = 0.50 h

Time taken by the train during its first trip

 

distance travelled
speed
300km
75 km/h
=4h
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distance travelled speed 300km 75 km/h =4h

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Step 2

For second half of the trip

Distance covered by train s2 = 300 km

Speed of the train v2 = 85 km/h

Time taken by the train during its second trip

distance travelled
speed
300km
85 km/h
-3.5h (rounded off value)
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distance travelled speed 300km 85 km/h -3.5h (rounded off value)

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Step 3

(a) Average speed of the trai...

total distance travelled
Average speed of the train
total time taken
(300+300) km
(4+3.5 .50)h
600
8
75km/h
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total distance travelled Average speed of the train total time taken (300+300) km (4+3.5 .50)h 600 8 75km/h

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