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Social ScienceA train makes a round trip on a straight, level track. The first half of the trip is 300km and is traveled at a speed of 75 km/m. After a 0.50 h layover, the train returns the 300km at the speed of 85 km/h. What is the train’s (a) average speed and (b) average velocity?
A train makes a round trip on a straight, level track. The first half of the trip is 300km and is traveled at a speed of 75 km/m. After a 0.50 h layover, the train returns the 300km at the speed of 85 km/h. What is the train’s (a) average speed and (b) average velocity?
Expert Answer
Given:
For first half of the trip
Distance covered by train s1 = 300 km
Speed of the train v1 = 75 km/h (assumed)
Layover time of the train = 0.50 h
Time taken by the train during its first trip
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distance travelled speed 300km 75 km/h =4h
For second half of the trip
Distance covered by train s2 = 300 km
Speed of the train v2 = 85 km/h
Time taken by the train during its second trip
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distance travelled speed 300km 85 km/h -3.5h (rounded off value)
(a) Average speed of the trai...
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total distance travelled Average speed of the train total time taken (300+300) km (4+3.5 .50)h 600 8 75km/h
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