A triangular plate with base 6 m and height 2 m is submerged vertically in water such that the highest vertex of the plate is 4 meters below the surface and the base is horizontal to the surface4 m2 m6 mExpress the hydrostatic force against one side of the plate as an integral and evaluate it. (Round your answer to the nearest whole number. Use 9.8 m/s2 for the acceleration due to gravity. Recall that the weightdensity of water is 1,000 kg/m3.)

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Asked Oct 16, 2019

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A triangular plate with base 6 m and height 2 m is submerged vertically in water such that the highest vertex of the plate is 4 meters below the surface and the base is horizontal to the surface
4 m
2 m
6 m
Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Round your answer to the nearest whole number. Use 9.8 m/s2 for the acceleration due to gravity. Recall that the weight
density of water is 1,000 kg/m3.)
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A triangular plate with base 6 m and height 2 m is submerged vertically in water such that the highest vertex of the plate is 4 meters below the surface and the base is horizontal to the surface 4 m 2 m 6 m Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Round your answer to the nearest whole number. Use 9.8 m/s2 for the acceleration due to gravity. Recall that the weight density of water is 1,000 kg/m3.)

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check_circleExpert Solution
Step 1

To determine the hydrostatic force against one side of the plate.

Step 2

Given:

density of water
1000kg /m3
89.8m/s2
4 m
2 m
6 m
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density of water 1000kg /m3 89.8m/s2 4 m 2 m 6 m

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Step 3

Concept Used:

The hydrostatic force on the one side of th...

Force = pvg
where
p density of fluid
v = volume of the fluid
g force due to gravity
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Force = pvg where p density of fluid v = volume of the fluid g force due to gravity

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