Question
Asked Nov 5, 2019
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A truck covers 40.0 m in 7.80 s while uniformly slowing down to a final velocity of 1.45 m/s.

(a) Find the truck's original speed.
m/s

(b) Find its acceleration.
m/s2
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Expert Answer

Step 1

To find:

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Given: (a) Distance covered, s = 40m Time taken, t= 7.8 s Final velocity, v = 1.45 m/s To find: (a)Original Speed or Initial velocity, u = ?? (b)Acceleration, a =??

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Step 2

Thus,

...
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We know: v = u + at or, 1.45 ua(7.8) or, u -Eql 1.45 a(7.8) Also, we know: s ut0.5at2 or, 40 (1.45-a(7.8)) (7.8) +0.5a(7.8) Putting the values of Eqi] or, 40 11.31 -30.42a 0.94 3m /s2 or, a Thus, from Eql u 1.45- a(7.8) or,u 1.45-(-0.943)(7.8) or,u 8.805m /s

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