A truck (M = 2500kg) collides with a car (m = 1000kg) at a 4-way intersection. Fortunately nobody gets hurt. Suppose the car is going north at 20m/s ( about 45mph) and the truck is coming from the east at 10m/s ( about 22mph). The car and truck stick together after the collision. (a) Find the speed and direction of the car and truck immediately after the collision. (b) Approximately how much energy went into the deformation of the metal that caused the two vehicles to stick together? (c) What assumptions did you make?

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter2: Motion In One Dimension
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Constants and other possibly useful numbers
g = 9.8m/s?
G = 6.67 × 10-11 Nm/kg?
c= 3 x 10°m/s
Radius of the Moon: 1.74 x 106m
Mass of the Sun: 2 x 1030kg
Radius of the Sun: 6.957 x 10°m
Mass of an electron me =9.11 x 10-31kg
Mass of a proton mp
1.67 x 10-27kg
%3D
Average distance between the Moon and Earth:
3.84 x 10 m
Average distance between Sun and Earth: 1.5 x
1011m
Mass of Earth: 6 x 1024kg
Radius of Earth: 6.4 x 106m
Mass of the Moon: 7.35 x 1022kg
Moments of Inertia:
R+ R
2.
MR²
1
2
I =Em;r? Iring = M
Idisk =ML Igphere =M R
= Icylinder =MR Irod
I disk
%3D
%D
%3D
12
The vector product or cross product between two vectors A and B can be calculated as follows:
If you know the angle 0 between the two vectors, find the magnitude of the product |C| = |Ã × B| =
|A||B| sin 0 and find the direction using the right-hand-rule.
%3D
Transcribed Image Text:Constants and other possibly useful numbers g = 9.8m/s? G = 6.67 × 10-11 Nm/kg? c= 3 x 10°m/s Radius of the Moon: 1.74 x 106m Mass of the Sun: 2 x 1030kg Radius of the Sun: 6.957 x 10°m Mass of an electron me =9.11 x 10-31kg Mass of a proton mp 1.67 x 10-27kg %3D Average distance between the Moon and Earth: 3.84 x 10 m Average distance between Sun and Earth: 1.5 x 1011m Mass of Earth: 6 x 1024kg Radius of Earth: 6.4 x 106m Mass of the Moon: 7.35 x 1022kg Moments of Inertia: R+ R 2. MR² 1 2 I =Em;r? Iring = M Idisk =ML Igphere =M R = Icylinder =MR Irod I disk %3D %D %3D 12 The vector product or cross product between two vectors A and B can be calculated as follows: If you know the angle 0 between the two vectors, find the magnitude of the product |C| = |Ã × B| = |A||B| sin 0 and find the direction using the right-hand-rule. %3D
A truck (M = 2500kg) collides with a car (m = 1000kg) at a 4-way intersection. Fortunately
nobody gets hurt. Suppose the car is going north at 20m/s ( about 45mph) and the truck is
coming from the east at 10m/s ( about 22mph). The car and truck stick together after the
%3D
collision.
(a) Find the speed and direction of the car and truck immediately after the collision.
(b) Approximately how much energy went into the deformation of the metal that caused the two
vehicles to stick together?
(c) What assumptions did you make?
The
Transcribed Image Text:A truck (M = 2500kg) collides with a car (m = 1000kg) at a 4-way intersection. Fortunately nobody gets hurt. Suppose the car is going north at 20m/s ( about 45mph) and the truck is coming from the east at 10m/s ( about 22mph). The car and truck stick together after the %3D collision. (a) Find the speed and direction of the car and truck immediately after the collision. (b) Approximately how much energy went into the deformation of the metal that caused the two vehicles to stick together? (c) What assumptions did you make? The
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