A tub containing 47 kg of water is placed in a farmer's canning cellar, initially at 10° C. On a cold evening the cellar loses thermal energy through the walls at a rate of 1200 J/s. Without the tub of water, the fruit would freeze in 4 h (the fruit freezes at -1° C because the sugar in the fruit lowers the freezing temperature).

Principles of Physics: A Calculus-Based Text
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By what time interval does the presence of the water delay the freezing of the fruit? The specific heat of water is c = 4180 J/kg⋅∘C
 
A tub containing 47 kg of water is placed in a farmer's canning cellar, initially at 10° C. On a cold evening the cellar loses thermal energy through the walls at a rate of 1200 J/s.
Without the tub of water, the fruit would freeze in 4 h (the fruit freezes at –1°C because the sugar in the fruit lowers the freezing temperature).
Transcribed Image Text:A tub containing 47 kg of water is placed in a farmer's canning cellar, initially at 10° C. On a cold evening the cellar loses thermal energy through the walls at a rate of 1200 J/s. Without the tub of water, the fruit would freeze in 4 h (the fruit freezes at –1°C because the sugar in the fruit lowers the freezing temperature).
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