Excel Data Analysis tool resultsMeanVariancet-Test: Two-Sample Assuming Unequal VariancesYes33.399449.693ObservationsHypothesized Mean Differencedft StatP(T ≤t) one-tailt Critical one-tailP(Tst) two-tailt Critical two-tailPrint130160.5800.2851.7460.5702.120DoneNo28.272348.0958- A two-sample test for means was conducted to determine if the completion time for continuing education programsfor nurses differed when costs are paid by employers (Yes) versus when individuals paid out of their own funds (NoThe Excel Data Analysis tool results are provided. Complete parts a through c below.Click the icon to view the Excel Data Analysis tool results.a. Explain how to use this information to draw a conclusion if the null hypothesis is Ho: Hy-HN ≤0. Clearly state thecorrect critical value and p-value and your conclusion.The alternative hypothesis is H₁

Introduction Hypothesis is as assumption that is being tested.

Answered: A two-sample test for means was…

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section10.4: Distributions Of Data

Problem 3GP

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Similar questions

A pooled variance estimate is useful for two-sample hypothesis tests of a normal mean when the underlying population variances can be considered equal. True or False?
A bank wants to determine whether a customer's current balance can be used to predict future earning potential. What would be the most appropriate procedure to use to analyze data to answer this question? Only choose a test that handles multiple comparisons if such a test is needed. O Chi-square test of association O ANOVA (Analysis of Variance) O Regression Test of Slope or Correlation O Test for a Difference of Proportions O Test for a Difference of Means
Perform the analysis of variance (ANOVA) at the 5% significance level to identify is there any difference in the mean between the three populations.
Estimate can be used to identify two general features for each of the several variance estimates in ANOVA. What are these features?
please explain how to use the standard deviation from the 1-Var Stats statistical output to obtain the variance of a data set
A bank wants to determine whether a customer's preference for using cash or credit can be used to predict whether they will answer the phone on a weekday evening. What would be the most appropriate procedure to use to analyze data to answer this question? Only choose a test that handles multiple comparisons If such a test is needed. Regression Test of Slope or Correlation O Test for a Difference of Proportions O Test for a Difference of Means O Chi-square test of association O ANOVA (Analysis of Variance)
Explain Analysis of variance (ANOVA)?
Females and males from the general adult population volunteer an average of 4.2 hours per week. A random sample of 21 female college students and 22 male college students and the hours they volunteer per week is given in the table below. At the 0.05 significance level, is there sufficient evidence to conclude that a difference exists between the mean number of volunteer hours per week for male and female college students? Male Female Sample Mean 2.7 3.9 Sample Standard Deviation 1.48 1.87 Sample Size 22 21 What is the p-value for this test? 0.0254 0.0978 2.33 38.096 0.0127
Females and males from the general adult population volunteer an average of 4.2 hours per week. A random sample of 21 female college students and 22 male college students and the hours they volunteer per week is given in the table below. At the 0.05 significance level, is there sufficient evidence to conclude that a difference exists between the mean number of volunteer hours per week for male and female college students? Male Female Sample Mean 2.7 3.9 Sample Standard Deviation 1.48 1.87 Sample Size 22 21 What is the decision for this test? Reject the null because the test statistic is in the critical region and the p-value is less than alpha. Fail to reject the null because the test statistic is in the critical region and the p-value is less than alpha. Fail to reject the null because the test statistic is not in the critical region and the p-value is less than alpha. Reject the null because the test statistic is in the…
Females and males from the general adult population volunteer an average of 4.2 hours per week. A random sample of 21 female college students and 22 male college students and the hours they volunteer per week is given in the table below. At the 0.05 significance level, is there sufficient evidence to conclude that a difference exists between the mean number of volunteer hours per week for male and female college students? Male Female Sample Mean 2.7 3.9 Sample Standard Deviation 1.48 1.87 Sample Size 22 21 What is the test statistic for this test? What is the critical value for this test? What is the p-value for this test? What is the decision for this test?
Describe the sources of within groups variance. How does within groups variance affect the range of between groups variance?

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