(а) у — 2х3D 2 у + 2х — — 1 y + (b) у — 2х 3D 0 2y + x = 0 (с) 2у — х %3D 2 2y + x = 3D -2 (d) у — 2х х + 2у 3 (е) 2х + у 3 -2 2у + x 3D ——2 — 2 -1

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The figure shows the graph of two perpendicular lines. Which of the following pairs of equations might have such a graph?

(а) у — 2х3D 2
у + 2х — — 1
y +
(b) у — 2х 3D 0
2y + x = 0
(с) 2у — х %3D 2
2y + x =
3D -2
(d) у — 2х
х + 2у 3
(е) 2х + у 3 -2
2у + x 3D ——2
— 2
-1
Transcribed Image Text:(а) у — 2х3D 2 у + 2х — — 1 y + (b) у — 2х 3D 0 2y + x = 0 (с) 2у — х %3D 2 2y + x = 3D -2 (d) у — 2х х + 2у 3 (е) 2х + у 3 -2 2у + x 3D ——2 — 2 -1
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