a) Using a sample size of 75, construct a 95% confidence interval estimate of the mean birth weight in the Apple County. b) Using a sample size of 75,000, construct a 95% confidence interval estimate of the mean birth weight in the Apple County. c) Which of the preceding confidence intervals is wider? Why?
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- Suppose that for a random sample of 200 firms that revalued their fixed assets, the mean ratio of debt to tangible assets was 0.517 and the sample standard deviation was 0.148. For an independent random sample of 400 firms that did not revalue their fixed assets, the mean ratio of debt to tangible assets was 0.489 and the sample standard deviation was 0.158. Find a 99% confidence interval for the difference between the two population means.A wildlife study is designed to find the mean weight of salmon caught by an Alaskan fishing company. find the minimum sample size needed in order to construct a 95% confidence interval for the mean weight of such Salmon, to within 0.20 pounds. Assume that standard deviation 2.10.A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.61 hours, with a standard deviation of 2.39 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.43 hours, with a standard deviation of 1.61 hours. Construct and interpret a 90%confidence interval for the mean difference in leisure time between adults with no children and adults with children μ1−μ2. Let μ1 represent the mean leisure hours of adults with no children under the age of 18 and μ2 represent the mean leisure hours of adults with children under the age of 18. -The 90% confidence interval for μ1−μ2is the range from____ hours to____hours. (Round to two decimal places as needed.) -What is the interpretation of this confidence interval? A. There is 90% confidence that the difference of the means is in the interval. Conclude that there is insufficient evidence of a significant difference…
- From a research survey, it was found that a random sample of 18 elementary graduates of an exclusive private school has a mean NEAT score of 90 with a standard deviation of 16, while a random sample of 24 elementary graduates of a public school showed a mean NEAT score of 85 with a standard deviation of 12. Is there a significant difference in the NEAT performance of these two groups of elementary graduates? a. Use the traditional method, and b. The P-value method c. Construct a 95% confidence interval for the difference in mean.2. In a length of hospitalization study conducted by several cooperating hospitals, a random sample of 64 peptic ulcer patients was drawn from a list of all peptic ulcer patients ever admitted to the participating hospitals and the length of hospitalization per admission was determined for each. The mean length of hospitalization was found to be 8.25 days. The population standard deviation is known to be 3 days. Calculate a 95% confidence interval for the population mean, and explain the interpretation of this interval.A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.03 hours, with a standard deviation of 2.46 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.48 hours, with a standard deviation of 1.52 hours. Construct and interpret a 90% confidence interval for the mean difference in leisure time between adults with no children and adults with children μ1−μ2. Let μ1 represent the mean leisure hours of adults with no children under the age of 18 and μ2 represent the mean leisure hours of adults with children under the age of 18. The 90%confidence interval for μ1−μ2 is the range from nothinghours to nothing hours. Also interpret the confidence interval. (Round to two decimal places as needed.)
- In the network of centers for minors in a certain region, it is necessary to check if for a certain group the average number of escape attempts by inmates is greater than 3, 20 minors are randomly selected, obtaining that the average number of attempts is 3.5 with a standard deviation of 2.7 For a confidence level of 99%, can it be considered that the average number of escape attempts is actually greater than the value initially proposed?A random sample of 4040 adults with no children under the age of 18 years results in a mean daily leisure time of 5.015.01 hours, with a standard deviation of 2.492.49 hours. A random sample of 4040 adults with children under the age of 18 results in a mean daily leisure time of 4.044.04 hours, with a standard deviation of 1.891.89 hours. Construct and interpret a 9595% confidence interval for the mean difference in leisure time between adults with no children and adults with children left parenthesis mu 1 minus mu 2 right parenthesisμ1−μ2. Let mu 1μ1 represent the mean leisure hours of adults with no children under the age of 18 and mu 2μ2 represent the mean leisure hours of adults with children under the age of 18. The 95% confidence interval for left parenthesis mu 1 minus mu 2 right parenthesisμ1−μ2 is the range from hours to hours.Suppose average pizza delivery times are normally distributed with an unknown population mean and a population standard deviation of six minutes. A random sample of 28 pizza delivery restaurants is taken and has a sample mean delivery time of 36 minutes. Find a 90% confidence interval estimate for the population mean delivery time.
- 1) An electronic manufacturer produces lampshades with a life span of approximately normally distributed with a standard deviation of 35 hours. a) If a sample of 50 bulbs has an average life span of 835 hours, construct a 95% confidence interval for the average life span of all the lampshades produced. Interpret the result. b) What must be the sample size if the manufacturer wishes to be 99% confident that the estimate is within 10 hours of the correct mean? Interpret the result.A paint manufacturer wants to determine the average drying time of a new interior wall paint. If for 12 test areas of equal size he obtained a mean drying time of 66.3 minutes and a standard deviation of 8.4 minutes, conduct a 95% confidence interval for the true mean .In order to help identify baby growth patterns that are unusual, we need to construct a confidenceinterval of the mean head circumference of all babies that are two months old. A random sample of 100babies is obtained, and the mean circumference is found to be 40.6 cm. Assuming that the populationstandard deviation is 1.6 cm, find a 99% confidence interval estimate of the mean head circumference ofall two-month-old babies.
